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Kay [80]
3 years ago
5

What type of reaction is radioactive decay?

Chemistry
1 answer:
anyanavicka [17]3 years ago
8 0
2. first order reaction
Hope I helped! :)
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You have used 2.4×102 L of distilled water for a dialysis patient. How many gallons of water is that?
Alinara [238K]

Answer:

63.36gallons

Explanation:

Given:

Volume of water used for dialysis = 2.4 x 10²L

Solution:

We are to convert from liters to gallons.

The conversion factor is shown below:

                1L = 0.264gallons

To convert to litre:

       since 1L = 0.264gallons

             2.4 x 10²L = (2.4 x 10² x 0.264)gallons; 63.36gallons

3 0
3 years ago
A salt solution with a volume of 250 mL that contains 0.70 mol NaCl.
uysha [10]
 <span>0.70 mol/0.250 L = 2.8 M</span>
5 0
3 years ago
Who no this i need help i need to pass to the next grade
Hitman42 [59]

Exothermic reactions is where  energy is released. Exothermic reactions are reactions that release energy into the environment in the form of heat. Exothermic reactions feel warm or hot or may even be explosive.

7 0
3 years ago
Ionization energy and electronegativity show similar trends in the periodic table. Describe these trends. What is the significan
marin [14]
Electronegativity measures how much an atom likes to pull electrons away from another one. Ionization energy measures how much an atom doesn't want to lose electrons. As an atom that wants to gain electrons will clearly not want to lose electrons, these trends are basically identical.
3 0
3 years ago
The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.
madam [21]

Answer: The pH of a 4.4 M solution of boric acid is 4.3

Explanation:

H_3BO_3\rightarrow H^+H_2BO_3^-

at t=0  cM              0             0

at eqm c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 4.4 M and \alpha = ?

K_a=5.8\times 10^{-10}

Putting in the values we get:

5.8\times 10^{-10}=\frac{(4.4\times \alpha)^2}{(4.4-4.4\times \alpha)}

(\alpha)=0.000011

[H^+]=c\times \alpha

[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M

Also pH=-log[H^+]

pH=-log[4.8\times 10^{-5}]=4.3

Thus pH of a 4.4 M H_3BO_3 solution is 4.3

3 0
3 years ago
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