1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goblinko [34]
3 years ago
6

A student makes a mistake while preparing a vitamin C sample for titration and adds the potassium iodide solution twice. How wil

l the larger quantity of KI influence the amount of NBS needed to titrate the sample? a. Increase it. b. Decrease it. c. Will have no effect on it.
Chemistry
1 answer:
LiRa [457]3 years ago
5 0

The added KI does not have any impact  

The reaction invovles Titration of vitaminc ( Ascorbic acid)

ascorbic acid + I₂ → 2 I⁻  +  dehydroascorbic acid

the excess iodine is free reacts with the starch  indicator, forming the blue-black starch-iodine complex.  

This is the endpoint of the titration. since alreay excess KI is added ( the source of Iodine), it does not have an influence.

Answer B

Hope this helps!

You might be interested in
Which substance loses electrons in a chemical reaction? the one that is oxidized, which is the oxidizing agent the one that is r
victus00 [196]

Answer:

The one that is oxidized or the reducing agent

Explanation:

Oxidation results in loss of electrons or an increase in oxidation state.

Reduction results in gain of electrons or  decrease in oxidation state.

The element that undergoes oxidation is said to oxidised, similarly the element that undergoes reduction is said to be reduced.

In a redox reaction, both oxidation and reduction takes place.

If a substrate undergoes oxidation or is oxidised, it is also responsible for reduction of the other species, as the total number of electrons should always be conserved.

The substance that undergoes oxidation, releases some electrons, these electrons are taken by the other substrate and it undergoes reduction.

Hence the substance that undergoes oxidation is called the reducing agent, as it is responsible for reduction of other substrate, when oxidizing itself.

Similar thought works for a substance that undergoes reduction or is reduced, works as an oxidizing agent.

7 0
3 years ago
Read 2 more answers
What is the total number of valence electrons in the dot structure of CBr4? Explain how you determined this answer. What is the
Mnenie [13.5K]

Answer:- There are 32 valence electrons and it's tetrahedral in shape.

Explanations:- Atomic number of carbon is 6 and it's electron configuration is 1s^22s^22p^2 . It has 4 electrons in the outer most shell means it has 4 valence electrons.

Atomic number of Br is 35 and it's electron configuration is 1s^22s^22p^63s^23p^64s^23d^1^04p^5 . It has 7 electrons in the outer most shell(2 in 4s and 5 in 4p) .

There is one C and four Br in the given compound. So, total number of valence electrons = 4+4(7) = 4+28 = 32

Four Br atoms are bonded to the central carbon atom and also there isn't any lone pair present on carbon. It makes it tetrahedral.

5 0
3 years ago
An isotonic solution has: a)The same pH as blood b) More ions per unit volume than blood c) More water per unit volume than blo
Veronika [31]

Answer:

d) osmotic pressure equal to that of blood

Explanation:

Answer is not a) because pH is concentration of positive hydrogen in solution but it not note all solutes. Answer is not b) because like answer a), it not note solutes without charge and, additionally it not note the pressure equilibrium when solvent flows through a membrane . Answer is not c) because it can be more or less water (solvent).

8 0
3 years ago
How many grams of o2(g) are needed to completely burn 70.2 g of C3H8(g)
Lubov Fominskaja [6]
First you must write a balanced chemical equation.

C3H8 + 5O2 --> 3CO2 + 4H2O

From there, we can set up the stoichiometry equation to solve.

g O2= 70.2 g C3H8 X (1 mol C3H8/44.0962g C3H8) X (5 mol O2/1 mol C3H8) X (31.998g O2/1 mol O2)

Now solve, and you should get 254.7 g O2. Hope this helped!
6 0
3 years ago
Polymers are large molecules composed of simple units repeated many times. Thus, they often have relatively simple empirical for
sp2606 [1]

Answer:

(a) C5H8O2

(b) C2H2Cl2

(c) CH2

(d) CH

Explanation:

We need to find the proportion of the atoms in whole numbers. Given the percentages we can calculate the number of moles and find their proportions.

Assume 100 g and given the atomic weights the moles are calculated.

(a) C = 59.9/ 12.01 = 4.98  ≈ 5.00

    H = 8.06/1.007 = 8.00

    O = 32/15.999  = 2.00

C5H8O2

(b) C= 24.8/12.01 = 2.06≈ 2.00

    H = 2.0/1.007 = 1.99 ≈ 2.00

   Cl = 73.1/ 35.453 = 2.06 ≈ 2.00

C2H2Cl2

(c) C = 86/12.01 = 7.16  

    H= 14/1.007 = 13.90

7.16:13.90 ≈ 1:2

CH2

(d) C = 92.30/12.01 = 7.68

    H = 7.7 / 1.007 =   7.65

7.68:7.65 ≈ 1:1

CH

6 0
3 years ago
Read 2 more answers
Other questions:
  • How to destermine the isotope
    5·1 answer
  • How many Ne atoms are contained in 32.0 g of the element?
    15·1 answer
  • (Extra points+Brainliest Answer, :) happy holidays)
    10·2 answers
  • Need help with question 1 a b and c also question 3 <br> ASAP help needed
    13·1 answer
  • What can be found in the Asteroid Belt?
    12·1 answer
  • Chemistry help!<br><br><br><br><br>Zoom in to see better!! ​
    7·1 answer
  • Which of these is not true about weight
    7·1 answer
  • Place the following in order of decreasing radius.<br><br> Te2- F- O2-
    6·1 answer
  • What are the terms that descripe these values for the element oxygen?
    7·1 answer
  • How does a conjugate acid differ from its conjugate base?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!