Answer:
Human sometimes also anerobically respite this happen usually during vigorous exercise when our heat and lungs are not able to supply enough oxygen to muscle and they carry out anaerobic respiration
Answer:
17.3 L
Explanation:
With all other variables held constant, you can find the missing volume using the Charles' Law equation:
V₁ / T₁ = V₂ / T₂
In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. Before we can solve, we need to convert Celsius to Kelvin (because we don't want negative numbers or temp. of 0).
V₁ = 20.0 L V₂ = ? L
T₁ = 0.00 °C + 273.15 = 273.15 K T₂ = -36.2 °C + 273.15 = 236.95 K
V₁ / T₁ = V₂ / T₂ <----- Charles' Law equation
20.0 L / 273.15 K = V₂ / 236.95 K <----- Insert values
0.0732 = V₂ / 236.95 K <----- Simplify left side
17.3 L = V₂ <----- Multiply both sides by 236.95
Answer:
COVALENT BOND
Explanation:
it is a chemical bond that involves the sharing of electrons.
Answer: 
at the temperature of the experiment is 0.56.
Explanation:
Moles of 
= 0.35 mole
Moles of 
= 0.40 mole
Volume of solution = 1.00 L
Initial concentration of = 
Initial concentration of = 
Equilibrium concentration of = 
The given balanced equilibrium reaction is,
Initial conc. 0.35 M 0.40 M 0 M 0M
At eqm. conc. (0.35-x) M (0.40-x) M (x) M (x) M
Given: (0.35-x) = 0.19
x= 0.16 M
The expression for equilibrium constant for this reaction will be,
![K_{eq}=\frac{[CO_2]\times [H_2]}{[CO]\times [H_2O]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BCO_2%5D%5Ctimes%20%5BH_2%5D%7D%7B%5BCO%5D%5Ctimes%20%5BH_2O%5D%7D)
Now put all the given values in this expression, we get :
Thus at the temperature of the experiment is 0.56.
