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galina1969 [7]
3 years ago
5

Is blacklight the same as ultraviolet?

Physics
1 answer:
Misha Larkins [42]3 years ago
6 0
Blacklight is made of a type of ultraviolet light called UV-A, but blacklight is not the same as ultraviolet light. Blacklight lamps only emit in the lower energy range of ultraviolet light.
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Mrs. Cooper rides the bus to work one morning. She sits on one of the bench seats and places her purse next to her on the seat.
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A daredevil is shot out of a cannon at 31.4 ◦ to the horizontal with an initial speed of 25.9 m/s. A net is positioned a horizon
Tanzania [10]

Answer:

The net should be placed at a height of 8.45 m

Explanation:

In order to calculate the height you have to apply the equations of <em>projectil motion.</em>

For x-axis, the position at a time t is given by:

Xf=Xo +(VoCosα)t (I)

Where Xf is the final position, Xo is the initial position, Vo is the initial speed and t is the time.

For the y-axis, the position at a time t is given by:

Yf=Yo + (VoSinα)t - 0.5gt^{2} (II)

Where Yf is the final position, Yo is the initial position, Vo is the initial speed, t is the time and g is the acceleration of gravity.

For both equations, ∝ is the angle formed by the cannon and the horizontal

The height where the net should be placed in order to catch the daredevil is given by replacing the time when the daredevil will be in the horizontal position of 39.7 m in the equation of position for the y-axis.

So, you have to calculate the time using (I)

Let the system of reference be placed at x=o and y=o

Xf= 0 + 25.9Cos(31,4◦)t

Xf=39.7

39.7=22.1t

Dividing both sides by 22.1 to find the value of t:

t=1.79 seconds

Replacing the time in equation (II) to find the height:

Yf=0 +25.9Sin(31,4◦)(1.79) - 0.5(9.8)1.79^{2}

Yf= 8.45 m

So the height is 8.45 m

4 0
4 years ago
<img src="https://tex.z-dn.net/?f=%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%
Verdich [7]

Answer:

1.7 × 10^1^0

Explanation:

Knowing that, the volume of the sphere is given by, v=\frac{4}{3}\pi ^3

Thus, the fractional change in volume is given by,

=3 × \frac{0.02}{100}=\frac{0.06}{100}

Pressure at the bottom of the sea is,

Δp =pgh = 10^3 × 10 × 10^3=10^7 pa.

Knowing that,

Bulk modulus: \frac{10^7 * 100}{0.06}=\frac{10^9}{6*10^-^2}=\frac{10^1^1}{6}

B =\frac{10}{6}*10^1^0

B = 1.7*10^1^0N/M^2

Answer = 1.7 × 10^1^0

[RevyBreeze]

5 0
2 years ago
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