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2 years ago

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A man jogs at a velocity of 2.5 m/s west for 1,200 s. He then walks at a velocity 1.0 m/s east for 500 s and then stops to rest

. What is the displacement of man when he stops to rest?

1 answer:

olganol [36]2 years ago

5 0

Speed of man towards West =2.5 m/s

Time to travel in the given direction = 1200 s

Total displacement towards west

$d_1 = v_1 t$

$d_1 = 2.5 \times 1200 = 3000 m$

Now speed of man towards East = 1 m/s

time to travel in east direction = 500 s

total displacement towards East

$d_2 = v_2 t$

$d_2 = 1 \times 500 = 500 m$

Now total displacement will be

$d = d_1 - d_2$

$d = 3000 - 500 = 2500 m$

so it is 2500 m towards west

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The magnitude of this charge is $q = 7.35\; {\rm \mu C}$ . Apply the unit conversion $1\; {\rm \mu C} = 10^{-6}\; {\rm C}$ :

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