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dsp73
2 years ago
9

Does gravity hold things together?

Physics
2 answers:
lorasvet [3.4K]2 years ago
5 0
Yes, Gravity is the force that holds everything one this Earth from flying away such as building and humans. The gravity is different for each planet as well. Earth has a gravity of one, and planets smaller than Earth have a Gravity lower than one meaning you can jump higher, because the force isn't strong enough to bring quickly. Planets bigger than Earth have a Gravity greater than 1 that allows for smaller jumps because they can bring you down quicker. There is gravity between the Earth and the Moon, and the Sun and all 8 Planets. In conclusion Gravity does hold things together.

If this helped please Mark as Brainliest! Thanks! ;)
mariarad [96]2 years ago
3 0
  <span>Gravity is an attractive force. All masses exert gravity, so matter pull toward each other. However, it is only significant when the masses are large, like that of Earth.  Exactly what causes gravity still remains a mystery. Since all the other three fundamental forces (strong, weak, and electromagnetic) are caused by particles called bosons, some scientists think that gravity is caused by particles called the graviton. However, such a particle has not yet been observed, and its existence has not been proven yet. 
Also, gravity does not hold EVERYTHING together, as another person has already mentioned. Static electricity holds your socks together after they come out of the dryer, not gravity. Also, gravity is too weak to hold together, say, the nucleus of atoms, or even atoms of molecules together.</span>
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A car manufacturer wants to change its car’s design to increase the car’s acceleration. Which changes should the engineers consi
likoan [24]

Answer:

The car manufacturers could increase bore of the cylinders, place the engine in the center or back of the car, add 1 to 2 turbochargers, and lower the center of gravity of the vehicle to increase traction.

Explanation:

Turbochargers would be recommended because they significantly increase both the torque of the engine as well as the amount of horses powering the car while also increasing original efficiency both with and without the additional power. Weight adjustment allows for lightweight vehicles with good traction. This is important to both keep control of the car under acceleration, but it also makes the vehicle more efficient due to the now sheddable unnecessary weight. A more obvious approach would be to increase the base horsepower and torque of the engine by increasing the bore of the cylinders and the weight of the pistons. This acts as an inertial lever, because the extra piston weight will drag the crankshaft faster. This could also be achieved by taking away piston weight, but this could be catastrophic should a piston slip.

4 0
3 years ago
A vehicle starts to move from the rest gets an acceleration of 5 m/s2 within 2
likoan [24]

Answer:

When an object moves in a straight line with a constant acceleration, you can calculate its acceleration if you know how much its velocity changes and how long this takes.

The formula is,

Acceleration = change in velocity / time taken

The equation for acceleration can also be represented as:

a = (v-u) \ t

The change in velocity v – u = 5 – 0 = 5 m/s.

The acceleration = change in velocity ÷ time = 5 m/s ÷ 2 s = 2.5 m/s^2

3 0
2 years ago
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Look at the velocity versus time graph below. What is the magnitude of the displacement of the object after it travels for three
Elza [17]

Answer:

C. 12m

Explanation:

veocity =  \frac{displacement}{time}

from the graph v = 4m/s and t = 3 s

d = vt = 4 × 3 = 12 m

5 0
2 years ago
wo parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude
melisa1 [442]

Answer:

<em> -18896.49 V/m</em>

<em></em>

Explanation:

Distance between the two plates = 10 cm = 10 x 10^{-2} m = 0.1 m

Also, one of the plates is taken as<em> zero volt.</em>

a. The potential strength between the zero volt plate, and 7.05 cm (0.0705 m) away is 393 V

b. The potential strength between the other plate, and 2.95 cm (0.0295 m) away is 393 V

<em>Potential field strength = -dV/dx</em>

where dV is voltage difference between these points,

dx is the difference in distance between these points

For the first case above,

potential field strength = -393/0.0705 = -5574.46 V/m

For the second case ,

potential field strength = -393/0.0295 = -13322.03 V/m

Magnitude of the field strength across the plates will be

-5574.46 + (-13322.03) = -5574.46 + 13322.03 =<em> -18896.49 V/m</em>

6 0
3 years ago
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ratelena [41]

Answer:

C?

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My best guess would be C as it's the only answer that gives a reason behind the statement.

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3 years ago
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