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3 years ago

For a particular experiment, Nadia must measure the following quantities:

Chemistry

2 answers:

rjkz [21]3 years ago

8 0

Answer:

Graduated cylinder

Stopwatch

Thermometer

Electronic Balance

Explanation:

The answers on Edge are above. (VERIFIED Edge Answer)

Make sure to click "thanks" and rate this answer to let others know this is the correct answer for this question.

Edge Tip: Answers do not mix or change.

g100num [7]3 years ago

4 0

Graduated cylinder
Stopwatch
Thermometer

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Use the image above and describe the

Lina20 [59]

Answer:

If you see in the image above, there is an unbalance force applied while playing tug of war. Since it is 1 vs 2, there is a greater net force in the right side then the left side. If it was 2 vs 2 or 1 vs 1, then they are appling balance force. You can also see in the picture that the arrows are pointing outwards (--->) rather then inwards (<---) because you are pulling the rope not pushing the rope. If you add one person on the left side, then the newtons which is 20N will become to 35N and will be balanced, but since there in only 1 person, there is less force on the left side, the newtons gets subtracted having only 20N. Since you are pulling the rope, the friction is opposite (<---). Since you are pulling the rope, you are using Kinetic force and the rope stays in potential force since it stays constant.

Hope this helps, thank you :) and I am not sure about magnitude I think you can that since there is greater force on the right side, there is more magnitude there.

4 0

3 years ago

A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati

prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

$k=\frac{2.303}{48.0}\log\frac{53500}{42520}$

$k=9.98\times 10^{-2}hr^{-1}$

Now we have to calculate the half-life.

$k=\frac{0.693}{t_{1/2}}$

$9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}$

$t_{1/2}=6.94hr$

Therefore, the half life of 28-Mg in hours is, 6.94

8 0

3 years ago

HELP ME PLEASE!!!

krok68 [10]

Answer:

Br (Bromine)

H (Hydrogen)

Explanation:

7 0

3 years ago

Read the list of substances. Wood, Iron, Sugar, Glass, Salt Which substances are highly soluble in water?

VLD [36.1K]

Salt and sugar would dissolve in the water, wood, iron, and glass wouldn't dissolve

5 0

3 years ago

Read 2 more answers

According to the combined gas law, the pressure exerted by a gas is:

sergij07 [2.7K]

Answer : The correct option is, (d) inversely proportional to volume and directly proportional to the kelvin temperature

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$

Charles' Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$

Combined gas law : It is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{PV}{T}=K$

or,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

From the above information we conclude that the pressure exerted by a gas is inversely proportional to volume and directly proportional to the kelvin temperature.

Hence, the correct option is, (d)

3 0

3 years ago