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zhenek [66]
3 years ago
9

True or False If the wavelength of a wave increases, its frequency also increases.

Physics
1 answer:
Degger [83]3 years ago
5 0
False, when wavelength waves increases the frequency will decreases. 
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When a driver hits the brakes, his car decelerates from 50m/s at a uniform rate of 2.0m/s^2. His car stops after covering some d
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Please find attached photograph for your answer. Please do comment whether it is useful or not.

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3 years ago
my friend wore a smart watch to bed,when he woke up in the morning it showed 300 steps taken how did this happen?
Ghella [55]

Answer:

Your tracker will detect your arm movement and will interpret it as steps so this is what it likely happening. Something similar happens while driving, if you go through a bumpy road or your car has a stiff suspension then this can cause the tracker to detect movement and count it as steps. Usually while driving and if you notice some vibration on your car or steering wheel you can try having your tracker a little bit more tight around your wrist and this will help decrease the amount of steps detected.

Explanation:

(Via AlvaroFitbit)

3 0
3 years ago
A 10-turn conducting loop with a radius of 3.0 cm spins at 60 revolutions per second in a magnetic field of 0.50T. The maximum e
bogdanovich [222]

Answer:

Maximum emf = 5.32 V

Explanation:

Given that,

Number of turns, N = 10

Radius of loop, r = 3 cm = 0.03 m

It made 60 revolutions per second

Magnetic field, B = 0.5 T

We need to find maximum emf generated in the loop. It is based on the concept of Faraday's law. The induced emf is given by :

\epsilon=\dfrac{d(NBA\cos\theta)}{dt}\\\\\epsilon=NBA\dfrac{d(\cos\theta)}{dt}\\\\\epsilon=NBA\omega \sin\omega t\\\\\epsilon=NB\pi r^2\omega \sin\omega t

For maximum emf, \sin\omega t=1

So,

\epsilon=NB\pi r^2\omega \\\\\epsilon=NB\pi r^2\times 2\pi f\\\\\epsilon=10\times 0.5\times \pi (0.03)^2\times 2\pi \times 60\\\\\epsilon=5.32\ V

So, the maximum emf generated in the loop is 5.32 V.

3 0
3 years ago
Astronomers have proposed the existence of an unexplained force that is causing the expansion of the universe to accelerate. Wha
irakobra [83]
The answer to your question would be D. Dark Energy

4 0
3 years ago
Read 2 more answers
A 11kg block slides up a 30° inclined plane at a constant velocity. The coefficient of friction between the block and the plane
astra-53 [7]

Answer:

The magnitude of the applied force is 94.74 N

Explanation:

Mass of the block, m = 11 kg

Angle of inclination of the plane, \theta = 30^{\circ}

Friction coefficient, \mu_{k} = 0.2

Now,

Normal force that acts on the block is given by:

F_{N} = mgcos\theta + Fsin\theta           (1)

Now, to maintain the equilibrium parallel to ramp the forces must be balanced.

Thus

Fcos\theta = \mu_{k}F_{N}                       (2)

From eqn (1) and (2)

Fcos\theta = \mu_{k}(mgcos\theta + Fsin\theta)

F(cos\theta - \mu_{k}sin\theta) = \mu_{k}mgcos\theta

F = \frac{\mu_{k}mgcos\theta}{cos\theta - \mu_{k}sin\theta}

F = \frac{0.2\times 11\times 9.8cos30^{\circ}}{cos30^{\circ} - 0.2\times sin30^{\circ}}

F = 94.74 N

3 0
3 years ago
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