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Blizzard [7]
3 years ago
8

I don’t even know how to start the problem. Can someone help?

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0
There’s not even a picture loading on my screen...
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Pls help ASAP NUMBER 2
Lisa [10]

Answer:

The answer to the question is 2 and 5

5 0
3 years ago
Read 2 more answers
How to solve the problem
lawyer [7]

Answer:

1440

Explanation:

1200 × .05 = 60

60 × 4 = 240

1200 + 240 = 1440

<h3><u>·</u><u>Hope</u><u> </u><u>I</u><u> </u><u>helped</u><u>,</u><u> </u><u>-</u><u>SunnySideHelper·</u></h3>
6 0
3 years ago
What is Permutations and Combinations?
marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}

Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.

5 0
2 years ago
(2a+9b-7).(-8)=help​
musickatia [10]

Answer:

(-16a)-72b+56

Step-by-step explanation:

Multiply 8 to each number

Hope this helped :)

4 0
3 years ago
Read 2 more answers
Eighth grade
Ymorist [56]

Answer:

b = 1

Step-by-step explanation:

Given the equation is:

- 5b + 2b - (-b) + 7 = 5

We separate the terms of b and the constants. To do that we subtract 7 from both the sides. We get:

- 5b + 2b - (-b) + 7 - 7 = 5 - 7

⇒ - 5b + 2b - (-b) = - 2

Now, simplifying the terms with 'b'.

⇒ -5b + 2b + b = - 2

⇒ (-5 + 2 + 1)b = - 2

⇒ -2b  = -2

Dividing both the sides by -2, we get:

b = 1 which is the required answer.

7 0
3 years ago
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