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Elena-2011 [213]
4 years ago
14

PLEASE HURRY WILL MARK BRAINLIEST IF CORRECT

Physics
1 answer:
Readme [11.4K]4 years ago
6 0

The answer to the question is 1.48 x 10^-11 J

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Marx believed that workers had a false consciousness and should develop a true consciousness instead. What does this mean?
Artyom0805 [142]

Answer:

That means they should actually pay attention.

Explanation:

8 0
4 years ago
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Energy is unable to change forms. please select the best answer from the choices provided t f
11111nata11111 [884]
Energy is unable to change forms. please select the best answer from the choices provided

<span>F - False</span>
5 0
4 years ago
Two long, parallel wires are separated by a distance of 2.60 cm. The force per unit length that each wire exerts on the other is
Alex777 [14]

Answer:

<em>10.75 A</em>

<em>The current is in opposite direction since it causes a repulsion force between the wires</em>

Explanation:

Force per unit length on the wires = 4.30×10^−5 N/m

distance between wires = 2.6 cm = 0.026 m

current through one wire = 0.52 A

current on the other wire = ?

Recall that the force per unit length of two wires conducting and lying parallel and close to each other is given as

F/l = \frac{u_{0}I_{1} I_{2}  }{2\pi r }

where F/l is the force per unit length on the wires

u_{0} = permeability of vacuum = 4π × 10^−7 T-m/A

I_{1} = current on the first wire = 0.520 A

I_{2} = current on the other wire = ?

r = the distance between the two wire = 0.026 m

substituting the value into the equation, we have

4.30×10^−5 = \frac{4\pi *10^{-7}*0.520*I_{2}  }{2\pi *0.026} =  \frac{ 2*10^{-7}*0.520*I_{2}  }{0.026}

4.30×10^−5 = 4 x 10^-6 I_{2}

I_{2} = (4.30×10^-5)/(4 x 10^-6) = <em>10.75 A</em>

<em>The current is in opposite direction since it causes a repulsion force between the wires.</em>

6 0
4 years ago
Saturn is 890,700,000 miles from the Sun. What is the distance in meters?
Maslowich

Answer:

1.4936 trillion meters

Explanation:

From an average distance of 886 million miles Saturn is 9.5 astronomical units away from the sun

6 0
3 years ago
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An 84.0 kg sprinter starts a race with an acceleration of 1.76 m/s2. If the sprinter accelerates at that rate for 11 m, and then
gulaghasi [49]

Answer:

t=17.838s

Explanation:

The displacement is divided in two sections, the first is a section with constant acceleration, and the second one with constant velocity. Let's consider the first:

The acceleration is, by definition:

a=\frac{dv}{dt}=1.76

So, the velocity can be obtained by integrating this expression:

v=1.76t

The velocity is, by definition: v=\frac{dx}{dt}, so

dx=1.76tdt\\x=1.76\frac{t^{2}}{2}.

Do x=11 in order to find the time spent.

11=1.76\frac{t^2}{2}\\ t^2=\frac{2*11}{76} \\t=\sqrt{12.5}=3.5355s

At this time the velocity is: v=1.76t=1.76*3.5355s=6.2225\frac{m}{s}

This velocity remains constant in the section 2, so for that section the movement equation is:

x=v*t\\t=\frac{x}{v}

The left distance is 89 meters, and the velocity is 6.2225\frac{m}{s}, so:

t=\frac{89}{6.2225}=14.303s

So, the total time is 14.303+3.5355s=17.838s

7 0
3 years ago
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