The first one would be thermal energy
Answer:
B = 0.8 T
Explanation:
It is given that,
Radius of circular loop, r = 0.75 m
Current in the loop, I = 3 A
The loop may be rotated about an axis that passes through the center and lies in the plane of the loop.
When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.
We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :
![\tau=NIAB\sin\theta](https://tex.z-dn.net/?f=%5Ctau%3DNIAB%5Csin%5Ctheta)
B is magnetic field
![B=\dfrac{\tau}{NIA\sin\theta}\\\\B=\dfrac{1.8}{1\times \pi \times (0.75)^2\times 3\times \sin(25)}\\\\B=0.8\ T](https://tex.z-dn.net/?f=B%3D%5Cdfrac%7B%5Ctau%7D%7BNIA%5Csin%5Ctheta%7D%5C%5C%5C%5CB%3D%5Cdfrac%7B1.8%7D%7B1%5Ctimes%20%5Cpi%20%5Ctimes%20%280.75%29%5E2%5Ctimes%203%5Ctimes%20%5Csin%2825%29%7D%5C%5C%5C%5CB%3D0.8%5C%20T)
So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.
Answer:
Low pressure systems typically arrive with storms and clouds. Air motion is usually upwards, as heated are is less dense and more buoyant than cooler air. A high pressure system is typically cooler than its counter-part, and skies are usually clear. Low pressure systems carry more water vapor due to rising hot air cooling and condensing.
So i say the power or the radius cortex in my equinox when i look at this V is the determination of V
True because my mom said to me this morning that i have to take my breakfast