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alexgriva [62]
4 years ago
8

How do activated charcoal water filters work

Chemistry
1 answer:
riadik2000 [5.3K]4 years ago
7 0

Carbon filtering is a method of filtering that uses a bed of activated carbon to remove contaminants and impurities, using chemical adsorption. ... Active charcoal carbon filters are most effective at removing chlorine, particles such as sediment, volatile organic compounds (VOCs), taste and odor from water.

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Which of two curves exhibits exponential growth
ExtremeBDS [4]

Answer:

The top curve/graph is exponential growth. All exponential growth graphs  look like a J in a way! Hope that helped

4 0
4 years ago
If 40 grams of NaCl was dissolved in 100 grams of water at 100 degrees Celsius, the solution would be.
lyudmila [28]

Answer:

saturated solution

Explanation:

4 0
2 years ago
At a given temperature, 4.06 atm of H2 and 3.5 atm of Cl2 are mixed and allowed to come to equilibrium. The equilibrium pressure
Llana [10]

<u>Answer:</u> The value of K_p for the given chemical reaction is 0.1415

<u>Explanation:</u>

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of the products and the reactants each raised to the power their stoichiometric ratios. It is expressed as K_p

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_p is written as:

K_p=\frac{p_{C}^cp_{D}^d}{p_{A}^ap_{B}^b}

For the given chemical equation:

H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g)

The expression for K_p for the following equation is:

K_p=\frac{(p_{HCl})^2}{(p_{H_2)}(p_{Cl_2})}

We are given:

p_{HCl}=1.418atm\\p_{H_2}=4.06atm\\p_{Cl_2}=3.5atm

Putting values in above equation, we get:

K_p=\frac{(1.418)^2}{(4.06)\times (3.5)}\\\\K_p=0.1415

The value of K_p for the given chemical reaction is 0.1415

5 0
3 years ago
If you were given 74.00 grams of Al, how many grains of Al2O3 would be produced?
Ket [755]
We are given the starting amount of Al metal to be used. This will be the starting point of the calculations. We do as follows:

74.00 g ( 1 mol / 26.98 g ) ( 1 mol Al2O3 / 2 mol Al ) ( 101.96 g / 1 mol ) = 139.83 g Al2O3 produced

Hope this answers the question. Have a nice day.
5 0
4 years ago
How many grams of i2 are needed to react with 30.1 g of n2h4?
Nina [5.8K]

The reaction is,

H2S + I2 --------------> 2 HI +S

Molar weight of H2S = 34 g per mol

Molar weight of HI =128 g per mol

Molar weight of I2 =254 g per mol

Moles of H2S in 49.2 g  = 49.2 /34 mol = 1.447 mol

So according to stoichiometry of the reaction, number of I2 mols needed                      

                                  = 1.447 mol

The mass of I2  needed = 1.447 mol x 254 g

8 0
3 years ago
Read 2 more answers
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