<u>Answer:</u> The molarity of HCl solution is 0.262 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Given mass of HCl = 0.3366 g
Molar mass of HCl = 36.5 g/mol
Volume of the solution = 35.23 mL
Putting values in above equation, we get:
Hence, the molarity of HCl solution is 0.262 M.
Answer:
50 g of K₂CO₃ are needed
Explanation:
How many grams of K₂CO₃ are needed to make 500 g of a 10% m/m solution?
We analyse data:
500 g is the mass of the solution we want
10% m/m is a sort of concentration, in this case means that 10 g of solute (K₂CO₃) are contained in 100 g of solution
Therefore we can solve this, by a rule of three:
In 100 g of solution we have 10 g of K₂CO₃
In 500 g of solution we may have, (500 . 10) / 100 = 50 g of K₂CO₃
Answer:
28
Explanation:
28 is correct. (NH4)2 is equal to 10 atoms. (8 H and 2 N ) CO3 is equal to 4 atoms. (1 C and 3 O) That's 14 atoms. But it's two molecules of this. So you just multiply by the number of molecules (2), and you get 28.
4Ag + 2H2S + O2 -> 2Ag2S + 2H20 i’m pretty sure that’s correct
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