1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lapatulllka [165]
3 years ago
5

When NASA's Skylab reentered the Earth's atmosphere on July 11, 1979, it broke into a myriad of pieces. One of the largest fragm

ents was a 1770-kg lead-lined film vault, and it landed with an estimated speed of 120 m/s.?
Physics
1 answer:
Burka [1]3 years ago
6 0

Answer:

Kinetic Enerrgy = 12744000 J or 12.744 MJ

Explanation:

Given Data:

Mass of fragment = m =1770 kg    ;

Estimated speed = v = 120 m/sec ;

Solution:

As we know that

Kinetic energy = K.E = (1/2)mv²

By putting the values, we get

              K.E = 0.5*1770*120²

              K.E = 12744000 J

                            or

              K.E = 12.744 MJ

So, the kinetic energy of lead-lined vault when it landed was 12.744MJ approximately.

You might be interested in
Which type of heat transfer can happen even if there are no particles of matter? A. Conduction B. Radiation C. Convection D. Ins
Naddik [55]

Heat can travel as<em> radiation</em>, even if there are no particles of matter
along the way.  Which is really lucky, because that's how we get
heat from the sun.  And light too.


3 0
3 years ago
Read 2 more answers
Susan's 12.0 kg baby brother Paul sits on a mat. Susan pulls the mat across the floor using a rope that is angled 30∘ above the
Pavlova-9 [17]

Answer:1.71 m/s

Explanation:

Given

mass of Susan m=12 kg

Inclination \theta =30^{\circ}

Tension T=29 N

coefficient of Friction \mu =0.18

Resolving Forces Along x axis

F_x=T\cos \theta -f_r

where f_r=friction\ Force  

F_y=mg-N-T\sin \theta

since there is no movement in Y direction therefore

N=mg-T\sin \theta

and f_r=\mu N

Thus F_x=T\cos \theta -\mu N

F_x=29\cos (30)-\0.18\times (12\times 9.8-29\sin (30))                

F_x=25.114-18.558

F_x=6.556 N

Work done by applied Force is equal to change to kinetic Energy

F_x\cdot x=\frac{1}{2}\cdot mv_f^2-\frac{1}{2}\cdot mv_i^2

6.556\times 2.7=\frac{1}{2}\cdot 12\times v_f^2

v_f^2=\frac{6.556\times 2.7\times 2}{12}

v_f^2=2.95

v_f=1.717 m/s        

8 0
3 years ago
The tongue weight of a trailer should be what percent of the gross trailer weight rating
mario62 [17]

Answer:

between 10 and 15 percent

Explanation:

How to put your load

- First load the heavy

The safe trailer starts loading correctly. Uneven weight can affect steering, brakes and swing control.

In general, 60% of the weight of the load should be in the front half of the trailer and 40% in the rear half (unless the manufacturer indicates something different). When you place the load, you want it to be balanced from side to side, keeping the center of gravity near the ground and on the axle of the trailer.

-  Hold your load

After balancing the load, you must hold it in place. An untapped load can move when the vehicle is moving and cause trailer instability.

- Trailer weight

To avoid overloading the trailer, look for the recommended weight rating. It is located on the VIN plate in the trailer chassis, usually on the tongue. Confirm the Gross Vehicle Weight Classification (GVWR) before towing.

GVWR: is the total weight that the trailer can support, including its weight. You can also find this number as the Gross Trailer Weight (GTW). The weight of the tongue should be 10-15% of the GTW.

7 0
3 years ago
6) If a mass of an object is decreased to half and acting force is reduced by quarter the acceleration of its motion
Zepler [3.9K]

Answer:

Decreases to half.

Explanation:

From the question given above, the following data were obtained:

Initial mass (m₁) = m

Initial force (F₁) = F

Initial acceleration (a₁) =?

Final mass (m₂) = ½m

Final force (F₂) = ¼F

Final acceleration (a₂) =?

Next, we shall determine a₁. This can be obtained as follow:

F₁ = m₁a₁

F = ma₁

Divide both side by m

a₁ = F / m

Next, we shall determine a₂.

F₂ = m₂a₂

¼F = ½ma₂

2F = 4ma₂

Divide both side by 4m

a₂ = 2F / 4m

a₂ = F / 2m

Finally, we shall determine the ratio of a₂ to a₁. This can be obtained as follow:

a₁ = F / m

a₂ = F / 2m

a₂ : a₁ = a₂ / a₁

a₂ / a₁ = F/2m ÷ F/m

a₂ / a₁ = F/2m × m/F

a₂ / a₁ = ½

Cross multiply

a₂ = ½a₁

From the illustrations made above, the acceleration of the car will decrease to half the original acceleration

7 0
3 years ago
2. A hanging wind-chime on a calm day would have kinetic or potential energy?
rjkz [21]

Answer:

it would have potential energy

7 0
3 years ago
Other questions:
  • What is N{2}+H{2}=NH{3}
    9·1 answer
  • How do scientist determine how old the world is and the fossils inside of it?
    7·4 answers
  • A 422N block is sitting on a frictionless surface and is connected by a massless, extension-less rope over a frictionless pulley
    11·1 answer
  • A suspicious-looking man runs as fast as he can along a moving sidewalk from one end to the other, taking 2.50 s. Then security
    7·2 answers
  • Consider the following hypotheses: 12:V ) &gt;(x)) Use rules of inference to prove that the following conclusion follows from th
    9·1 answer
  • In a closed system with no friction, a red sphere of 2.5 kg stands stationary. A blue sphere with a mass of 5.8 kg approaches th
    15·1 answer
  • Which state or states of matter take(s) the shape of it’s container
    14·1 answer
  • What is the answer to this question?
    7·1 answer
  • An object travels a distance d with acceleration a over a period of time t according to the equation: d = at² After 2.3 seconds
    8·1 answer
  • What is the velocity of a Usain Bolt if he runs 200 m in 10 seconds?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!