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Lapatulllka [165]
3 years ago
5

When NASA's Skylab reentered the Earth's atmosphere on July 11, 1979, it broke into a myriad of pieces. One of the largest fragm

ents was a 1770-kg lead-lined film vault, and it landed with an estimated speed of 120 m/s.?
Physics
1 answer:
Burka [1]3 years ago
6 0

Answer:

Kinetic Enerrgy = 12744000 J or 12.744 MJ

Explanation:

Given Data:

Mass of fragment = m =1770 kg    ;

Estimated speed = v = 120 m/sec ;

Solution:

As we know that

Kinetic energy = K.E = (1/2)mv²

By putting the values, we get

              K.E = 0.5*1770*120²

              K.E = 12744000 J

                            or

              K.E = 12.744 MJ

So, the kinetic energy of lead-lined vault when it landed was 12.744MJ approximately.

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The tibia is a lower leg bone (shin bone) in a human. The maximum strain that the tibia can experience before fracturing corresp
IRISSAK [1]

Answer:

a

   k    =  11600000 N/m

b

   \Delta  L  =  3.2323 *10^{-5} \ m

c

  F =  3750.28 \  N  

Explanation:

From the question we are told that

    The Young modulus is  E =  1.4 *10^{10} \  N/m^2

     The length is  L  =  0.35 \ m

      The  area is  2.9 \ cm^2  =  2.9 *10^{-4} \ m ^2

   

Generally the force acting on the tibia is mathematically represented as

       F =  \frac{E *  A  *  \Delta  L }{L}    derived from young modulus equation

Now this force can also be mathematically represented as

      F =  k *  \Delta  L    

So

     k    =  \frac{E *  A  }{L}

substituting values

     k    =  \frac{1.4 *10^{10} *  2.9 *10^{-4}  }{ 0.35}

     k    =  11600000 N/m

    Since the tibia support half the weight then the force experienced by the tibia is  

        F_k  =  \frac{750 }{2}  =  375 \  N

 From the above equation the extension (compression) is mathematically represented as

          \Delta  L  =  \frac{ F_k  *  L  }{ A *  E }        

substituting values

           \Delta  L  =  \frac{  375   *  0.35  }{ (2.9 *10^{-4}) *   1.4*10^{10} }

           \Delta  L  =  3.2323 *10^{-5} \ m

From the above equation the maximum force is  

        F =  \frac{1.4*10^{10} *  (2.9*10^{-4})  *  3.233*10^{-5} }{ 0.35}  

         F =  3750.28 \  N  

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An object travels along a right triangle with sides 3 m, 4 m, and 5 m. It returns back to the initial position.
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What is 1113.28 in a sig fig?
Afina-wow [57]

Answer:

6 significant figure

Explanation:

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