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SOVA2 [1]
3 years ago
5

As the mass number of the isotopes of hydrogen increases, the number of protons

Chemistry
1 answer:
Mariulka [41]3 years ago
4 0
It’s C they remain the same! Hope this helps! :)
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Calculate the pka of hypochlorous acid. The ph of a 0.015 m solution of hypochlorous acid has a ph of 4.64.
o-na [289]

Answer:

  • pKa = 7.46

Explanation:

<u>1) Data:</u>

a) Hypochlorous acid = HClO

b) [HClO} = 0.015

c) pH = 4.64

d) pKa = ?

<u>2) Strategy:</u>

With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.

<u>3) Solution:</u>

a) pH

  • pH = - log [H₃O⁺]

  • 4.64 = - log [H₃O⁺]

  • [H_3O^+]= 10^{-4.64} = 2.29.10^{-5}

b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)

c) Equilibrium constant: Ka =  [ClO⁻] [H₃O⁺] / [HClO]

d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M

e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M

f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46

5 0
3 years ago
What’s the density if the mass is 40.8g and the volume is 60mL?
luda_lava [24]

Answer:

We have the final answer as

<h2>0.68 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 40.8 g

volume = 60 mL

The density is

density =  \frac{40.8}{60}  \\

We have the final answer as

<h3>0.68 g/mL</h3>

Hope this helps you

8 0
3 years ago
Which is a property of a base? (Chemistry test need help please)
OleMash [197]
The answer is C . Watery feel
5 0
3 years ago
A 10.0cm3 volume of alcohol has a mass of 7.05g. What the density
VMariaS [17]

A 10.0cm3 volume of alcohol has a mass of 7.05g. 0.705 \frac{g}{c m^{3}} is the density

Answer:  0.705 \frac{g}{c m^{3}}

<u>Explanation:</u>

The ratio between the mass of a substance and its unit volume is referred as density.

\text {Density}=\frac{\text { mass }}{\text { volume }}=\frac{7.05 g}{10.0 \mathrm{cm}^{3}}=0.705 \frac{g}{\mathrm{cm}^{3}} is the Answer

<u>Note:</u>

1000 g = 1 kg

100 cm = 1 m

When we used to transform the given values into S.I units, then

\text {Density}\left(\frac{k g}{m^{3}}\right)=\frac{\text {Mass}(k g)}{\text {Volume}\left(m^{3}\right)}

Alcohol’s volume can be written as, 10.0 c m^{3} = 10 \times 10^{-2} m^{3}

Alcohol’s mass can denote as, 7.05 g = 7.05 \times 10^{-3} \mathrm{kg}

Then, \text { Density }\left(\frac{k g}{m^{8}}\right)=\frac{, 00705(k g)}{0.1\left(m^{3}\right)} = .0705 \frac{\mathrm{kg}}{\mathrm{m}^{\mathrm{s}}}

4 0
3 years ago
What would happen if cell differentiation did not happen during the<br> development of the embryo?
pishuonlain [190]

Answer:

Without the process of cell differentiation, multicellular organisms would not be possible.

3 0
3 years ago
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