Question

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500. ML flask with 3.0 atm of ammonia gas, and when the mixture has come to equilibrium measures the amount of nitrogen gas to be 0.90 atm . Calculate the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.

Answer 1

Answer:

12. is the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture.

Explanation:

$2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$

initially

3.0 atm      0              0

At equilibrium

(3.0-2p)     p               3p

Equilibrium partial pressure of nitrogen gas = p = 0.90 atm

The expression of a pressure equilibrium constant will be given by :

$K_p=\frac{p_{N_2}\times (p_{H_2})^3}{(p_{NH_3})^2}$

$K_p=\frac{p\times (3p)^3}{(3.0-2p)^2}$

$=\frac{0.90 atm\times (3\times 0.90 atm)^3}{(3.0-2\times 0.90 atm)^2}$

$K_p=12.30\approx 12.$

12. is the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture.