Explanation:
An acid is a substance that interacts with water to produce excess hydroxonium ions, H₃O⁺ in an aqueous solution.
The hydroxonium ions formed by the chemical bonding between the oxygen of water molecules and the protons released by the acid due to its excess ionization.
For example:
HCl + H₂O ⇄ H₃O⁺ + Cl⁻
acid water hydroxonium chloride
A base is a substance that interacts with water to yield excess hydroxide ions, OH⁻ in an aqueous solutions:
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
Ammonia water ammonium hydroxide
These explanations are based on the arrhenius theory.
learn more:
Bronsted-lowry theory brainly.com/question/4083753
Acid reaction brainly.com/question/5273689
#learnwithBrainly
Answer:
A
Explanation:
gravity pulls us down so we don't float away
Answer:
mass=56.12kg
Explanation:
PE=mgh
4620=m×9.8×8.4
make m subject of the formula...
m =4620/(9.8×8.4)
m=4620/82.32
m=56.12kg
Ans: R = Ball Travelled = 92.15 meters.
Explanation:
First we need to derive that formula for the "range" in order to know how far the ball traveled before hitting the ground.
Along x-axis, equation would be:

Since there is no acceleration along x-direction; therefore,

Since

and

=0; therefore above equation becomes,

--- (A)
Now we need to find "t", and the time is not given. In order to do so, we shall use the y-direction motion equation. Before hitting the ground y ≈ 0 and a = -g; therefore,
=>

=>

Since

; therefore above equation becomes,

Put the value of t in equation (A):
(A) =>

Where x = Range = R, and

; therefore above equation becomes:
=>

Now, as:

and

°
and g = 9.8 m/(s^2)
Hence,
Ans: R = 92.15 meters.-i
Answer:
I hope the picture below help.
Explanation: