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DedPeter [7]
3 years ago
7

The salts NaCl and CaCl

Chemistry
1 answer:
Irina18 [472]3 years ago
6 0
The answer is 8 :)
All nobel gases have 8 outer electrons.
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How do ecosystems respond to natural disasters such as fires and floods?
Dafna11 [192]

Answer:

How do ecosystems respond to natural disasters such as fires and floods :

Explanation:

They recover in stages, gradually returning to the original system. … She plans to create various physical and biological disturbances in the ecosystem to see how populations change over time.

3 0
2 years ago
The density of methanol is 0.787 g/ml. What is the mass in grams of 25.0 ml of methanol? Give your answer with the correct unit
Sveta_85 [38]

Answer:

19.6 g is the mass of methanol

Explanation:

Density of methanol is 0.787 g/mL.

Density means mass / volume

Methanol density = Methanol mass / Methanol volume.

Let's replace in the formula

0.787 g/mL = Methanol mass / 25 mL

0.787 g/mL . 25 mL = Methanol mass → 19.6 g

8 0
3 years ago
S this equation balanced and in the lowest form? 4NH3 → 2N2 + 6H2
Mrrafil [7]
No it is not. the balanced equation is 2NH3 = N2 + 3H2
3 0
3 years ago
Which metal is more active than H2?<br> (1) Ag (3) Cu<br> (2) Au (4) Pb
astraxan [27]

Answer is (4) - Pb.


According to the reactivity series of elements

- the elements which are above the hydrogen are more reactive than hydrogen.

- the elements which are below the hydrogen are less reactive than hydrogen.


Among the given choices, only Pb is placed above the hydrogen in the reactivity series and rest are below the hydrogen.


Hence, Pb is more active than hydrogen.

5 0
3 years ago
One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
PSYCHO15rus [73]

Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

5 0
3 years ago
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