Answer:
Explanation:
1 ) tire of radius 0.381 m rotating at 12.2 rpm
12.2 rpm = 12.2 /60 rps
n = .20333 rps
angular speed
= 2πn
= 2 x 3.14 x .20333
= 1.277 rad / s
2 ) a bowling ball of radius 12.4 cm rotating at 0.456 rad/s
angular speed = .456 rad/s
3 ) a top with a diameter of 5.09 cm spinning at 18.7∘ per second
18.7° per second = (18.7 / 180) x 3.14 rad/s
= .326 rad/s
4 )
a rock on a string being swung in a circle of radius 0.587 m with
a centripetal acceleration of 4.53 m/s2
centripetal acceleration = ω²R
ω is angular velocity and R is radius
4.53 = ω² x .587
ω = 2.78 rad / s
5 )a square, with sides 0.123 m long, rotating about its center with corners moving at a tangential speed of 0.287 m / s
The radius of the circle in which corner is moving
= .123 x √2
=.174 m
angular velocity = linear velocity / radius
.287 / .174
1.649 rad / s
The perfect order is
4 ) > 5> 1 >2>3.
Answer:
c
Explanation:
energy doesnt affect to mass of a object
Answer:
gravitational potential energy of 10 kg mass is 122.625 J
Explanation:
Gravitational Potential energy gain is given as
here we know that
m = 10 kg
h = 1.25 m
now from above formula we have
So gravitational potential energy of 10 kg mass is 122.625 J
Answer:
4.29 millimeters
Explanation:
Bats emit ultrasound waves: in air, ultrasound waves travel at a speed of
The frequency of the waves emitted by this bat is:
Therefore we can find the wavelength of the wave emitted by the bat by using the relationship between speed, frequency and wavelength:
3rd nearest planet.
Neighborhood of Sun.
Orion arm.
Milky Way galaxy.
Local cluster.
13.8 billion years.
Universe.
Mind of God.
