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2 years ago

Over 60 billion dollars a year are spent on ___________. (Points : 10) Corrections Intermediate sanctions Probation Parole

Chemistry

1 answer:

meriva2 years ago

6 0

Over 60 billion dollars a year are spent on Corrections.

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What is a solution of zinc and copper?<br>five letter word

Lana71 [14]

Answer:

Brass

Explanation:

Brass is an alloy of copper and zinc, in proportions which can be varied to achieve varying mechanical and electrical properties.

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2 years ago

What is the cation name for alcl3?

Elden [556K]

The name is Aluminum Cloride

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2 years ago

Read 2 more answers

What could we use to measure the energy of particles when we are unable to see them

iVinArrow [24]

Answer:

Temperature.

Explanation:

Temperature is a measure of the average kinetic energy of a system.

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2 years ago

How many parts per million of fluoride in a solution that is 500 grams of fluoride and 500,000 liters water

erik [133]

0.000001‬ppm

Explanation:

Mass of fluoride = 500g

Volume of water = 500000liters

Unknown:

Parts per million of fluoride = ?

Solution:

The parts per million is the amount of solute in milligram dissolved in a liter of water or milligram per kilogram of solvent

It is a unit used to express very small concentration.

we need to convert g - mg

500g = 500 x 10⁻³mg = 0.5mg

Concentration in parts per million = $\frac{mass in mg}{Volume in liters}$

Concentration in parts per million = $\frac{0.5}{500000}$ = 0.000001‬ppm

learn more:

Parts per million brainly.com/question/2854033

#learnwithBrainly

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3 years ago

A 13 g sample of P4010 contains how many

Alex777 [14]

Answer:

$\large \boxed{5.5 \times 10^{22}\text{ molecules of P$_{2}$O}_{5}}$

Explanation:

You must calculate the moles of P₄O₁₀, convert to moles of P₂O₅, then convert to molecules of P₂O₅.

1. Moles of P₄O₁₀

$\text{Moles of P$_{4}$O}_{10} = \text{13 g P$_{4}$O}_{10} \times \dfrac{\text{1 mol P$_{4}$O}_{10}}{\text{283.89 g P$_{4}$O}_{10}} = \text{0.0458 mol P$_{4}$O}_{10}$

2. Moles of P₂O₅

P₄O₁₀ ⟶ 2P₂O₅

The molar ratio is 2 mol P₂O₅:1 mol P₄O₁₀

$\text{Moles of P$_{2}$O}_{5} = \text{0.0458 mol P$_{4}$O}_{10} \times \dfrac{\text{2 mol P$_{2}$O}_{5}}{\text{1 mol P$_{4}$O}_{10}} = \text{0.0916 mol P$_{2}$O}_{5}$

3. Molecules of P₂O₅

$\text{No. of molecules} = \text{0.0916 mol P$_{2}$O}_{5} \times \dfrac{6.022 \times 10^{23}\text{ molecules P$_{2}$O}_{5}}{\text{1 mol P$_{2}$O}_{5}}\\\\= \mathbf{5.5 \times 10^{22}}\textbf{ molecules P$_{2}$O}_{5}\\\text{There are $\large \boxed{\mathbf{5.5 \times 10^{22}}\textbf{ molecules of P$_{2}$O}_{5}}$}$

6 0

3 years ago