Hi there, your question was incomplete, so I will be solving a similar question so it would help you to understand how to answer these types of questions
Q) A chemist must dilute 22.5mL of 119μ M aqueous silver(II) oxide AgO solution until the concentration falls to 65.0μ M . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Round your answer to significant digits.
Answer:
<u>Final Volume V2 = 41.2 mL</u>
Explanation:
We will start by first recalling the formula of dilution which goes by,
M1 * V1 = M2 * V2 ------------------------------(1)
Now let us consider V1 = 22.5 mL
M1 = 119μ M
M2 = 65.0μ M
lets substitute the values above in equation 1,
M1 * V1 = M2 * V2
V2 = (M1 * V1)/M2 ( I have created V2 as the subject here)
V2 = (119*22.5)/65
<u>V2 = 41.2 mL</u>
Energy is "the ability to do work". Energy is how things change and move. It takes energy to cook food, to drive to school, and to jump in the air. Different forms of Energy. Energy can take a number of different forms.
It is fiery because it is cooled molten magma
<h2>
Answer:</h2>
Workdone = 601.33 Nm
<h2>
Explanation:</h2>
Workdone = Force(F) x horizontal distance(d).
Wordone = F x d
Where F is the horizontal component of the force
Force = 35 pounds
Recall that;
1 pound force = 4.4N
=> 35 pounds = 35 x 4.4N = 154N
=> Force = 154N
But since the rope makes a 10⁰ angle with the ground,
The horizontal component of the force F is Force x cos10⁰
=> F = 154 cos 10⁰
=> F = 154 x 0.9848
=> F = 151.66N
Horizontal distance (d) = 13 feet
Recall that;
1 foot = 0.305m
=> 13 feet = 13 x 0.305m = 3.965m
=> d = 3.965m
=> Substituting the values of F and d into the equation above, we have;
Workdone = F x d
Workdone = 151.66N x 3.965m
Workdone = 601.33Nm
False it <span>the SI unit of power, equivalent to one joule per second, corresponding to the power in an electric circuit in which the potential difference is one volt and the current one ampere.</span>