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MissTica
3 years ago
9

1. Write the balanced equation for the breakdown of hydrogen peroxide. The equation has been written, you just have to balance.

Chemistry
2 answers:
Mnenie [13.5K]3 years ago
8 0

Explanation:

A balanced equation is defined as the equation which contains same number of atoms on both reactant and product side.

For example, H_{2}O_{2} \rightarrow H_{2}O + O_{2}

Number of atoms on reactant side are as follows.

  • H = 2
  • O = 2

Number of atoms on product side are as follows.

  • H = 2
  • O = 3

Therefore, balance this equation by multiplying H_{2}O_{2} by 2 on reactant side. Thus, the balanced chemical equation is as follows.

         2H_{2}O_{2} \rightarrow H_{2}O + O_{2}

o-na [289]3 years ago
7 0
The balanced equation is attached in the image below. The coefficients are 2, 2, blank.

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Hii pls helpnme to write out the ionic equation ​
Oxana [17]

Answer:

CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)

Explanation:

According to this question, sodium carbonate reacts with sulfuric acid to form aqueous sodium sulfate, carbon dioxide and water. The balanced chemical equation is as follows:

Na2CO3(aq) + H2SO4(aq) → Na2SO4(aq) + CO2(g) + H2O(l)

- Next, split compounds that are aqueous into ions.

2Na+(aq) + CO32-(aq) + 2H+(aq) + SO42-(aq) → 2Na+(aq) + SO42-(aq) + CO2(g) + H2O(l)

- Next, we cancel out the spectator ions, which are ions that remain the same in the reactants and products side of a chemical reaction. The spectator ions in this equation are 2Na+(aq) and SO42-(aq).

CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)

- Hence, the balanced ionic equation is as follows:

CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)

3 0
3 years ago
What is the pH of a 4.08*10-'M solution of H30+?
Mariana [72]

Answer:

8.4

Explanation:

-log(4.08x10^-9) = 8.4

- Hope that helped! Please let me know if you need further explanation.

4 0
3 years ago
Explain how lone pairs of electrons influence the shape of a molecule.
Ronch [10]

Explanation:

the lone pairs will be negatively charged. these have a repulsion effect on other negatively charged electrons in the shells of atoms. picture a water molecule: the lone electron pair on the top of the oxygen will have a repulsion force on the 2 hydrogen atom's orbiting electrons to cause a bent molecular geometry.

3 0
3 years ago
Carry out the following operations as if they were calculations of experimental results and express each answer in standard nota
Shalnov [3]

Answer:

1. 10.6\; \rm m (one decimal place.)

2.0.79\; \rm g (two decimal places.)

3. 16.5\;\rm cm^2 (three significant figures.)

Explanation:

<h3>1.</h3>

The first and second expressions are additions and subtractions. When adding two numbers, the accuracy of the result is given by the number of decimal places in it. The result should have as many decimal places as the input with the least number of decimal places.

For example, in the first expression:

  • 5.6792\;\rm m has four decimal places.
  • 0.6\; \rm m has only one decimal place.
  • 4.33\; \rm m has two decimal places.

Therefore, the result should be rounded to one decimal place. Note that these units are compatible for addition, since they are all the same. The result should have the same unit (that is: \rm m.)

Therefore:

\rm 5.6792\; m + 0.6\; m + 4.33\; m \approx 10.6\; \rm m. (Rounded to one decimal place.)

<h3>2.</h3>

Similarly:

  • \rm 3.70\; \rm g has two decimal places.
  • 2.9133\; \rm g has four decimal places.

Therefore, the result should be rounded to two decimal places. Its unit should be \rm g (same as the unit of the two inputs.)

\rm 3.70\; g - 2.9133\; g \approx 0.79\; \rm g. (Rounded to two decimal places.)

<h3>3.</h3>

When multiplying two numbers, the accuracy of the result should be based on the number of significant figures in it. The result should have as many significant figures as the input with the least number of significant figures. In this expression:

  • 4.51\; \rm cm has three significant figures.
  • 3.6666\; \rm cm has five significant figures.

Therefore, the result should have only three significant figures.

The unit of the result is supposed to be the product of the units of the input. In this expression, that unit will be \rm cm \cdot cm, which is occasionally written as \rm cm^2.

\rm 4.51 \; cm \times 3.6666 \; cm \approx 16.5\; \rm cm^2. (Rounded to three significant figures.)

7 0
3 years ago
The rate of effusion of an unknown gas was measured and found to be 11.9 mL/min. Under identical conditions, the rate of effusio
iren2701 [21]

Answer : The correct option is, (B) CO_2

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of unknown gas = 11.9\text{ mL }min^{-1}

R_2 = rate of effusion of oxygen gas = 14.0\text{ mL }min^{-1}

M_1 = molar mass of unknown gas  = ?

M_2 = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{11.9\text{ mL }min^{-1}}{14.0\text{ mL }min^{-1}})=\sqrt{\frac{32g/mole}{M_1}}

M_1=44.2g/mole

The unknown gas could be carbon dioxide (CO_2) that has approximately 44 g/mole of molar mass.

Thus, the unknown gas could be carbon dioxide (CO_2)

5 0
3 years ago
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