Answer:
The angular velocity is
5.64rad/s
Explanation:
This problem bothers on curvilinear motion
The angular velocity is defined as the rate of change of angular displacement it is expressed in rad/s
We know that the velocity v is given as
v= ωr
Where ω is the angular velocity
r is 300mm to meter = 0.3m
the radius of the circle
described by the level
v=1.64m/s
Making ω subject of the formula and solving we have
ω=v/r
ω=1.64/0.3
ω=5.46 rad/s
Light is refracted when it crosses the interface from air to glass in which it moves more slowly.
Since the light speed changes at the interface, the wave length of the light must change too. The wave length decreases as the light enter the medium and the light wave changes direction.
Answer:
Force on the proton will be 
Explanation:
We have given speed of proton is 20.3% of speed of light
Speed of light 
So speed of proton 
Magnetic field B = 0.00629 T
Charge on proton 
Angle between velocity and magnetic field 
Force on the proton is equal to 
Answer:
C. -0.6
Explanation:
Line is passing through the points ( - 3, 1) & (2, - 2)
Slope of line
