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solniwko [45]
4 years ago
11

What is the focal length of a concave mirror that magnifies, by a factor of +3.2, an object that is placed 30 cm from the mirror

?
A. 23cm
B. 32cm
C. 44cm
D. 46cm
Physics
1 answer:
vazorg [7]4 years ago
8 0

Answer:

C. 44 cm

Explanation:

We can solve the problem by using the lens equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p = 30 cm is the distance of the object from the mirror

q is the distance of the image from the mirror

We also know that the magnification is

M=-\frac{q}{p}=+3.2

So

q=-3.2p=-3.2(30)=-96 cm

Substituting into the first equation, we find f:

\frac{1}{f}=\frac{1}{30}-\frac{1}{96}=0.0229 cm^{-1} \rightarrow f=43.7 cm \sim 44 cm

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A phone cord is 2.28 m long. The cord has a mass of 0.2 kg. A transverse wave pulse is produced by plucking one end of the taut
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The characteristics of the speed of the traveling waves allows to find the result for the tension in the string is:  

         T = 10 N

The speed of a wave on a string is given by the relationship.

      v =\sqrt{\frac{T}{\mu } }

Where   v es the velocty, t is the tension ang μ is the lineal density.

They indicate that the length of the string is L = 2.28 m and the pulse makes 4 trips in a time of t = 0.849 s, since the speed of the pulse in the string is constant, we can use the uniform motion ratio, where the distance traveled e 4 L

           v = \frac{d}{t}  

           v = \frac{4 L}{t}  

           v = \frac{4 \ 2.28 }{0.849}  

            v = 10.7  m / s

Let's find the linear density of the string, which is the length of the mass divided by its mass.

            μ = \frac{m}{L}  

            \mu = \frac{0.2}{2.28}  

            μ = 8.77 10⁻² kg / m

The tension is:

        T = v² μ

Let's calculate

        T = 10.7²  8.77 10⁻²

        T = 1 0 N

In conclusion using the characteristics of the velocity of the traveling waves we can find the result for the tension in the string is:

         T = 10 N

Learn more here:  brainly.com/question/12545155

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3 years ago
Is this unbalanced force or is it balanced also is it technically acceleration?
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Unbalanced

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There is an acceleration. Look at the direction of the arrows.

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Explanation:

Delta x Δx stands for displacement, or change in position.

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If the rate of change of the magnetic field applied to a loop of wire is doubled, what happens to the induced emf in that loop a
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Answer:

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Explanation:

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