Answer:
The top of the window is 0.5 m below the sill of the upper window
Explanation:
We have the time the pot takes to fall a distance y- yo = 2.0 m and g = 9.8, from this we can calculate the velocity of the pot when it just reached the top of the window in question. Take the positive y direction to be downward
y-yo=vo*t+I/2gt^2
vo=(y-yo-I/2gt^2)/t
vo=3.138 m/s
The flowerpot falls from rest and we have the velocity it gains until it reaches the top of the window below, from this information we can get the distance between the sill and the top of the window below.
v^2=vo^2+2g(y-yo)
y-yo=(v^2-vo^2)/2g
= 0.5 m
The top of the window is 0.5 m below the sill of the upper window
Trying to figure this out
Answer:
The center mass (Xcm) of the two mass = (M₁X₁ + M₂X₂)/(M₁ +M₂)
Explanation:
let the first mass = M
let the position of second = M
Answer:
Explanation:
For example, an ice cube has heat energy and so does a glass of lemonade. If you put the ice in the lemonade, the lemonade (which is warmer) will transfer some of its heat energy to the ice.
Answer:
Explanation:
Volume of block A = 10 x 6 x 1 = 60 cm³
Mass of block A = 630 g
density of mass A = mass / density
= 630 / 60 = 10.5g / cm³
Volume of block B = 5 x 5 x 3 = 75 cm³
Mass of block A = 604 g
density of mass A = mass / density
= 604 / 75 = 8.05 g / cm³
Since density of both A and B are less than that of mercury , both will float in mercury.
