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Igoryamba
4 years ago
9

What exactly are the physical properties of a candle that has been blown out?

Chemistry
1 answer:
pogonyaev4 years ago
4 0
Let's think, if you have a candle ( that is not blown out ) the physical properties are the candles mass and hence ( hence of the candle is the stiffness of the candle), weight, length, density, surface friction ( force resisting the relative motion of solid surface), and the energy content. You then, need to go to bed, so, therefore, you want to blow the candle out. Once you blow the candle out, the candle is evidently going to have at least a couple of different physical properties, than before it was blown out. The physical properties are a different color, the length of the candle, the texture, you could also apply the mass of the candleholder, and then, the mass of the candleholder and the candle, last but not least, the mass of just the candle. Once you observe the candle, you should be able to plug in those observations into the physical properties. As to, because you asked' what are the physical properties of a candle that has been blown out... We are going to assume that we did observe the candle, and the length of the candle in cm, after being blown out is 30cm. (12 inches; customary). Next, that the color of the candle is the same (let us say the original color is taffy pink).  We can then say that the texture of the candle is waxy and the top and smooth as you get to the bottom ( the texture depends on how long the candle was burning, but we are saying that we lit the candle, and then immediately blew the flame out ) . We now have the mass of the candleholder, which will scientificity stay the same. Now, for the mass of the candleholder and the candle, that all depends of how long you let it burn ( remember, we are saying we lit the wick and then immediately  blew the fame out ). So, the candle really didn't change is mass, so, therefore, wouldn't affect the mass of the candleholder including the candle. That also goes to the mass of the candle.
 
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irina1246 [14]

A large activation energy is required to break the double bonds of unsaturated hydrocarbons.

<h3>What are Unsaturated hydrocarbons ?</h3>

Unsaturated hydrocarbons are defined as the hydrocarbons in which double or triple bonds are present between two adjacent carbon atoms. They are known as alkenes and alkynes respectively. The general formula for these hydrocarbons is CnH2n and CnH2n-2

  • In unsaturated hydrocarbons, more number of bonds are formed, thus the bond strength of the bonds formed will be more because the orbitals come closer to each other.
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Learn more about Unsaturated hydrocarbons here:

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2 years ago
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DedPeter [7]

Answer:

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Explanation:

5 0
3 years ago
2.In a titration, 25.00 cm3 of a solution of hydrochloric acid reacted with 18.40 cm3 of sodium hydroxide solution of concentrat
telo118 [61]

Answer:

0.11mol/dm³

Explanation:

The reaction expression is given as:

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Volume of base  = 18.4cm³ = 0.0184dm³

Concentration of base  = 0.15mol/dm³

Solution:

The concentration of hydrochloric acid = ?

 To solve this problem, let us first find the number of moles of the base;

 Number of moles  = concentration x volume

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Therefore,  0.00276mol of the base will combine with  0.00276mol of HCl

 So;

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4 0
3 years ago
A chef plans to mix 100% vinegar with italian dressing. the italian dressing contains 13% vinegar. the chef wants to make 150 mi
charle [14.2K]
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For the first equation, we do a mass balance:

mass of 100% vinegar + mass of 13% vinegar = mass of 42% vinegar

Assuming they have the same densities, then we can write this equation in terms of volume.

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For the second equation, we do a component balance:

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x + y = 150
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Therefore, you need to mix 50 mL of the 100% vinegar and 100 mL of the 13% vinegar.

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D.) There must be an equal number of atoms of each element on both sides of the equation

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3 years ago
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