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djyliett [7]
3 years ago
13

Please help i cant find any answers...

Chemistry
2 answers:
Hitman42 [59]3 years ago
8 0

Answer:

98.8

Explanation:

CsF + XeF6 --> CsXeF7

37.8g ................. ?g

37.8g CsF x (1 mol CsF / 151.9g CsF) x (1 mol CsXeF7 / 1 mol CsF) x (397.2g CsXeF7 / 1 mol CsXeF7) = 98.8g CsXeF7 .......... to three significant digits

N76 [4]3 years ago
3 0

Answer:

28.0

Explanation:

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The P:OP:O ratio is the amount of inorganic phosphate incorporated into ATP per atom of oxygen consumed. It represents the coupl
Ray Of Light [21]

Answer:

For NADH; P:O = 2.5

For FADH ₂; P : O = 1.5

Explanation:

The P:O (phosphate:oxygen) ratio represents the amount of inorganic phosphate, Pi used per atom of oxygen consume to synthesize ATP.

The Chemiosmotic theory predicts H⁺:O and H⁺:ATP ratios. Experimentally these appear to be 10 and 4 respectively when NADH is the substrate, equivalent to a P:O ratio of 2.5, and 6 and 4 respectively for FAD-linked substrates (e.g. succinate), equivalent to a P:O ratio of 1.5.

1. Electron flow from NADH to O₂ pumps protons at three sites to yield 3 ATP (P:O = 2.5)

For NADH: 10 H ⁺ translocated/O (2e -)

ATP/2e - = (10 H⁺/ 4 H +) = 2.5  

2. Succinate (via FADH2) bypasses site 1 giving 2 ATP (P : O = 1.5)

For FADH ₂= 6 H ⁺/O(2e - )

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3 years ago
What would be the freezing point of a 1.7 mole aqueous ethylene glycol solution? The freezing point depression constant for wate
nata0808 [166]

Answer:

-3.2^oC

Explanation:

In order to answer this question, we need to be familiar with the law of freezing point depression. The law generally states that mixing our solvent with some particular solute would decrease the freezing point of the solvent.

This may be expressed by the following relationship:

\Delta T_f=iK_fb

Here:

\Delta T_f=T_{initial}-T_{final} is the change in the freezing point of the solvent given its initial and final freezing point temperature values;

i is the van 't Hoff factor (i = 1 for non-electrolyte solutes and i depends on the number of moles of ions released per mole of ionic salt);

K_f is the freezing point depression constant for the solvent;

b=\frac{n_{solute}}{m_{solvent}} is molality of the solute, defined as a ratio between the moles of solute and the mass of solvent (in kilograms).

We're assuming that you meant 1.7-molal solution, then:

b=1.7 m

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i=1

The freezing point depression constant:

K_f=1.86^oC/m

Initial freezing point of pure water:

T_{initial}=0.00^oC

Rearrange the equation for the final freezing point and substitute the variables:

T_f=T_o-iK_fb=0.00^oC-1\cdot1.86^oC/m\cdot1.7 m=-3.16^oC

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