Since the molecules of a gas are constantly in motion, moving and hitting other gas molecules in all directions of the enclosed container, the molecules transfer a portion of energy through the interaction of other gas particles as they hit, but then bounce off.
This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:
Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻ ⇒2K⁺O⁻²H⁺ + I₂⁰
Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻
Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.
In such a way, the correct choice is C.
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Explanation:
k so basically u gotta do 59/1000000 then multiply that by 972 which gives u 0.057348
Answer:
The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is 
Explanation:
Given :
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:
= Rydberg energy
n = principal quantum number of the orbital
Energy of 11th orbit = 
Energy of 10th orbit = 
Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.
(Planck's' equation)
The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is
