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blagie [28]
3 years ago
11

Suppose your teacher asks you to separate a mixture of sand and water. Which of the following methods would you use: distillatio

n, filtration, or evaporation? Explain your answer.
Chemistry
2 answers:
weqwewe [10]3 years ago
8 0
To separate, filtration would work best. Sand particles and water molecules differ drastically in size. So when filtered, the sand would not flow out of the device as the water would. This will effectively separate the water and sand with the smallest amount of material lost.

Hope this helps :)
larisa86 [58]3 years ago
7 0
Depends, does the teacher just care about the water and sand being separated or does the teacher want you to separate them and still have both substances in their original form. If the teacher just cares about the separation I'd use evaporation. It was still water and sand the only thing is the water changed forms and became a gas. If the teacher wants both substances in their original state then I'd use filtration. You can separate the sand from the water and still have them both.
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Find the mass of an object on earth if its weight is 100N
Kaylis [27]

Answer:

0.19 kg

8 N

1.964 N

58.86 N

15 kg

Explanation:

w = Weight of an object = 100 N

g = Acceleration due to gravity of Earth = 9.81\ \text{m/s}^2

m = Mass of an object

Weight is given by

w=mg\\\Rightarrow m=\dfrac{w}{g}\\\Rightarrow m=\dfrac{100}{9.81}\\\Rightarrow m=10.19\ \text{kg}

Mass of the object is 0.19 kg

g = 2\ \text{m/s}^2

m = 4 kg

w=mg\\\Rightarrow w=4\times 2\\\Rightarrow w=8\ \text{N}

Weight of the object is 8 N.

m = 200 g

w=mg\\\Rightarrow w=0.2\times 9.81\\\Rightarrow w=1.964\ \text{N}

Weight of the object is 1.964 N.

Weight is the force the Earth exerts on an object which is on the surface of the Earth.

m = 6kg

w=mg\\\Rightarrow w=6\times 9.81\\\Rightarrow w=58.86\ \text{N}

The force of the object is 58.86 N.

w = 150 N

a = g = 10\ \text{m/s}^2

m=\dfrac{w}{g}\\\Rightarrow m=\dfrac{150}{10}\\\Rightarrow m=15\ \text{kg}

Mass of the object is 15 kg.

7 0
3 years ago
What happens to the speed of motion of the particles of a gas when a certain volume of the gas is heated at constant pressure? E
Likurg_2 [28]

Answer:

As the gas is heated, the particles will begin to move faster. ... Because the gas remains at a constant pressure and volume, the particles cannot spread out so they simply move around the container even faster.

4 0
3 years ago
Enthalpies of reaction calculated from bond energies and from enthalpies of formation are often, but not always, close to each o
jolli1 [7]

The enthalpy change in a reaction is given by-

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

This can be expressed in terms of bond energy as-

ΔH°rxn = BEreactants - BEproducts

Therefore, the calculated bond energy according to the above equation will be-

ΔH°rxn = [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H) ] - [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H)  = 0 kJ/mol

<h3>What is enthalpy change?</h3>

Enthalpy change is a measure of the energy emitted or consumed in a reaction. This can be determined using the following equation which involves standard enthalpy of reactant and product formation:

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

<h3>What is bond energy?</h3>

Bond energy is defined as the amount of energy needed to dissociate a mole of molecules into their individual atoms.

Learn more about the Enthalpy Change here:

brainly.com/question/14047927

#SPJ4

6 0
2 years ago
1: At which temperature would a reaction withΔH = -102 kJ/mol, ΔS = -0.188 kJ/(mol×K) be spontaneous? 2: At which temperature wo
Naddik [55]

Answer:

1: At temperatures below 542.55 K

2: At temperatures above 660 K

Explanation:

Hello there!

In this case, according to the thermodynamic definition of the Gibbs free energy, it is possible to write the following expression:

\Delta G=\Delta H-T\Delta S

Whereas ΔG=0 for the spontaneous transition. In such a way, we proceed as follows:

1:

0=\Delta H-T\Delta S\\\\T=\frac{-102kJ/mol}{-0.188kJ/mol-K} \\\\T=542.55K

It means that at temperatures lower than 542.55 K the reaction will be spontaneous.

2:

0=\Delta H-T\Delta S\\\\T=\frac{132kJ/mol}{0.200kJ/mol-K} \\\\T=660K

It means that at temperatures higher than 660 K the reaction will be spontaneous.

Best regards!

7 0
3 years ago
How many atoms of Sn are in 0.796 moles of this element?
garik1379 [7]

Answer:

savsdfasfsewce

Explanation:

afsfsfdsfesdfsdgsdgdg

3 0
3 years ago
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