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blagie [28]
3 years ago
11

Suppose your teacher asks you to separate a mixture of sand and water. Which of the following methods would you use: distillatio

n, filtration, or evaporation? Explain your answer.
Chemistry
2 answers:
weqwewe [10]3 years ago
8 0
To separate, filtration would work best. Sand particles and water molecules differ drastically in size. So when filtered, the sand would not flow out of the device as the water would. This will effectively separate the water and sand with the smallest amount of material lost.

Hope this helps :)
larisa86 [58]3 years ago
7 0
Depends, does the teacher just care about the water and sand being separated or does the teacher want you to separate them and still have both substances in their original form. If the teacher just cares about the separation I'd use evaporation. It was still water and sand the only thing is the water changed forms and became a gas. If the teacher wants both substances in their original state then I'd use filtration. You can separate the sand from the water and still have them both.
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Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2H2S(g) 3O2(g)2H2O(l) 2SO2
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Answer:

\Delta _rH=-1124.14kJ/mol

Explanation:

Hello!

In this case, since the standard enthalpy change for a chemical reaction is stood for the enthalpy of reaction, for the given reaction:

2H_2S(g) +3O_2(g)\rightarrow 2H_2O(l) +2SO_2(g)

We set up the enthalpy of reaction considering the enthalpy of formation of each species in the reaction at the specified phase and the stoichiometric coefficient:

\Delta _rH=2\Delta _fH_{H_2O,liq}+2\Delta _fH_{SO_2,gas}-2\Delta _fH_{H_2S,gas}-3\Delta _fH_{O_2,gas}

In such a way, by using the NIST database, we find that:

\Delta _fH_{H_2O, liq}=-285.83kJ/mol\\\\\Delta _fH_{SO_2, gas}=-296.84kJ/mol\\\\\Delta _fH_{O_2,gas}=0kJ/mol\\\\\Delta _fH_{H_2S,gas}=-20.50kJ/mol

Thus, we plug in the enthalpies of formation to obtain:

\Delta _rH=2(-285.73kJ/mol)+2(-296.84kJ/mol)-2(-20.50kJ/mol)-3(0kJ/mol)\\\\\Delta _rH=-1124.14kJ/mol

Best regards!

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