Answer:
just search it up you'll get ur answer
A factor that remains the same no matter the situation is called an independent variable. The variable that changes is called the dependent variable and will depend on what the independent variable is.
I’m Not Fa Sure but I really think is 45n hope it help sorry and good luck
Answer:
Explanation:
Given
mass of wheel m=13 kg
radius of wheel=1.8 m
N=469 rev/min
![\omega =\frac{2\pi \times 469}{60}=49.11 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%5Cfrac%7B2%5Cpi%20%5Ctimes%20469%7D%7B60%7D%3D49.11%20rad%2Fs)
t=16 s
Angular deceleration in 16 s
![\omega =\omega _0+\alpha \cdot t](https://tex.z-dn.net/?f=%5Comega%20%3D%5Comega%20_0%2B%5Calpha%20%5Ccdot%20t)
![\alpha =\frac{\omega }{t}=\frac{49.11}{16}=3.069 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%5Cfrac%7B%5Comega%20%7D%7Bt%7D%3D%5Cfrac%7B49.11%7D%7B16%7D%3D3.069%20rad%2Fs%5E2)
Moment of Inertia ![I=mr^2=13\times 1.8^2=42.12 kg-m^2](https://tex.z-dn.net/?f=I%3Dmr%5E2%3D13%5Ctimes%201.8%5E2%3D42.12%20kg-m%5E2)
Change in kinetic energy =Work done
Change in kinetic Energy![=\frac{I\omega ^2}{2}-\frac{I\omega _0^2}{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7BI%5Comega%20%5E2%7D%7B2%7D-%5Cfrac%7BI%5Comega%20_0%5E2%7D%7B2%7D)
![\Delta KE=\frac{42.12\times 49.11^2}{2}=50,792.34 J](https://tex.z-dn.net/?f=%5CDelta%20KE%3D%5Cfrac%7B42.12%5Ctimes%2049.11%5E2%7D%7B2%7D%3D50%2C792.34%20J)
(a)Work done =50.79 kJ
(b)Average Power
![P_{avg}=\frac{E}{t}=\frac{50.792}{16}=3.174 kW](https://tex.z-dn.net/?f=P_%7Bavg%7D%3D%5Cfrac%7BE%7D%7Bt%7D%3D%5Cfrac%7B50.792%7D%7B16%7D%3D3.174%20kW)
it is size of of particles because it does not matter about the size in a closed container