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sergij07 [2.7K]
3 years ago
11

What is an example of vaporization?

Physics
2 answers:
Alenkasestr [34]3 years ago
7 0

Answer:

just search it up you'll get ur answer

Phoenix [80]3 years ago
5 0
Boiling water is what I would put
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Create a story of a “day in the life of a water drop”. Your story should be creative and include all 6 steps in the water cycle.
pogonyaev

Answer:

Explanation:

Ok so first: the evaporation part, the sun starts to get warmer I ( the water droplet) rises up to the sky to start my evaporation cycle

Condensation: part: when I am in the air I change into a gas and then I change back into a liquid and gather my friends and make a cloud

Precipitation: as it gets to crowded, we can’t hold it anymore, when I cool down I like to sky dive with my cousins, snow, rain, sleet, hail which is called precipitation.

Then finally we land on the ground, we run down hills, and run into lakes surface runoff happens when there’s too many of us so some of us can’t be rain. Infiltration: when some of us soak into the ground cause we can’t make it into the streams and oceans. Ok I can’t help much more cause I’m super busy but if you need more help just message me and I can help thx ! Hope I helped Atleast a bit for you to understand more

5 0
3 years ago
Read 2 more answers
Find electric field at point p which is a distance l away from the both +q and -q
denis-greek [22]

Answer:

\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }

Where

  • q is the charge
  • r is the distance
  • E is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }

F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

⇒

F1+F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

8 0
3 years ago
Two toroidal solenoids are wound around the same form so that the magnetic field of one passes through the turns of the other. S
dedylja [7]

The concept that we need here to give a proper solution is mutual inductance.

The mutual inductance  is given by the expression

M=\frac{N\Phi}{I}

Where,

I = current

N = Number of turns

\Phi =Flux through the solenoid.

Part A) Then we have in our values that,

I=6.6A

\Phi= 3.50*10^{-2}Wb

N=450

Replacing in the equation,

M = \frac{450*350*10^{-2}}{6.60}

M = 2.39H

Part B) Here is required the Flux, then using the same expression we have that

\Phi = \frac{IM'}{N}

We conserve the same value for the Inductance but now we have a current of 2.6, then

\Phi = \frac{2.6*2.39}{690}

\Phi = 9*10^{-3}Wb

Therefore the flux in Solenoid 1 is 9*10^{-3}Wb

8 0
3 years ago
A square-based shipping crate is being designed that must contain a volume of 16 ft3 . The material that is used for the base an
Vlada [557]

Answer:

Explanation:

Given

volume V=16 ft^3

Suppose base is square with side L

height of crate is h

Volume V=L^2\times h

16=L^2\times h

Cost of top and bottom area c_1=3L^2

Cost of Side area c_2=4Lh\times 2=8Lh=8L\times \frac{16}{L^2}=\frac{128}{L}

Total Cost C=c_1+c_2

Total Cost C=3L^2+\frac{128}{L}

Differentiate C w.r.t Length

\frac{dC}{dL}=6L-\frac{128}{L^2}

L^3=\frac{128}{6}

L=2.75 ft

h=\frac{16}{2.75^2}=11.46 ft

Dimensions are L\times L\times h=2.75\times 2.75\times 11.46    

6 0
2 years ago
Your friend says an appliance uses energy. How would you correct his statement?
madreJ [45]

Answer:

Not all appliances run on energy. Some of them run on gas. Some both. It just depends on the age of the appliance, the make of the appliance, and the company who made it.

3 0
2 years ago
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