What is the volume of the regular pyramid below?
2 answers:
The picture in the attached figure
we know that
volume of the regular pyramid=(1/3)*area of the base*height
area of the base=12*12-----> 144 units²
height=71 units
substitute
volume of the regular pyramid=(1/3)*144*71-----> 3408 units³
the answer is
3408 units³
we know that
volume of the regular pyramid=(1/3)*area of the base*height
area of the base=12*12-----> 144 units²
height=71 units
substitute
volume of the regular pyramid=(1/3)*144*71-----> 3408 units³
the answer is
3408 units³
Answer:
Option d.
Step-by-step explanation:
Consider the below figure attached with this question.
From the given figure it is clear that the measure side of base is 12 units and height is 71 units.
The base of the pyramid is a square. So the area of base is
The volume of a regular pyramid is
where, B is area of base and h is height of the pyramid.
Substitute B=144 and h=71 in the above formula.
The volume of regular pyramid is 3408 cubic units.
Therefore, the correct option is d.
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Answer:
3.897
Step-by-step explanation:
equilateral triangles are also equiangular, meaning the have equal angles.
Triangle sum theory says that angles of a triangle add up to 180.
That means each angle is 60.
A = bh/2
You need the (h). The base of is 3. Perimeter = 9, so each side is 3
Draw a perpendicular line for the height. The line cuts the base in half (1.5)
Using trigonometry you can find the height.
tan 60° = h/1.5
h = height, 1.5 is half of 3, 60° is the base angle.
multiply each side by 1.5
1.5(tan 60°) = h
h=2.598
then substitute h into formula
A= <u>(2.598)(3) </u>
2
A = 3.897 rounded