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nekit [7.7K]
3 years ago
7

The “Big Bang” is an example of what type of scientific statement? A. A law B.a hypothesis C. A theory D. An equation

Physics
2 answers:
Andrej [43]3 years ago
7 0
C. Theory. It’s called the Big Bang theory for a reason
Ugo [173]3 years ago
6 0

Answer:

theory

Explanation:

that's why it's called the Big Bang Theory

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A machine shop worker reports the mass of an aluminum cube as 176 g. If one side of the cube measures 4 cm, what is the density
Zarrin [17]

-- Since it's a cube, its length, width, and height are all the same 4 cm .

-- Its volume is (length x width x height) = 64 cm³ .

-- Density = (mass) / (volume)

                = (176 g) / (64 cm³) 

                =         2.75 gm/cm³ .

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Recycled plastics cannot be used to produce new food containers because ___
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they cannot be sterilized

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Total these measurements. Your answer should indicate the proper accuracy. Be sure to include the units in your answer. (Remembe
vivado [14]

Answer:

10

Explanation:

This is tough. The last number  0.2 has only one significant figure. So while the sum of all the numbers is 12.3, you must only leave one sig figure. Rounding to the tenths gives 10.  

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4 years ago
Which statement best summarizes the theory of evolution by natural selection?
prisoha [69]

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c is the one that makes the most sense

Explanation:

8 0
3 years ago
Read 2 more answers
10. A hockey puck with mass 0.3 kg is sliding along ice that can be considered frictionless. The puck’s velocity is 20 m/s when
SVEN [57.7K]

Answer:

d = \frac{v^2_i}{2a}= \frac{(20m/s)^2}{2* 3.43 m/s^2}=58.309m

Explanation:

For this case  we can use the second law of Newton given by:

\sum F = ma

The friction force on this case is defined as :

F_f = \mu_k N = \mu_k mg

Where N represent the normal force, \mu_k the kinetic friction coeffient and a the acceleration.

For this case we can assume that the only force is the friction force and we have:

F_f = ma

Replacing the friction force we got:

\mu_k mg = ma

We can cancel the mass and we have:

a = \mu_k g = 0.35 *9.8 \frac{m}{s^2}= 3.43 \frac{m}{s^2}

And now we can use the following kinematic formula in order to find the distance travelled:

v^2_f = v^2_i - 2ad

Assuming the final velocity is 0 we can find the distance like this:

d = \frac{v^2_i}{2a}= \frac{(20m/s)^2}{2* 3.43 m/s^2}=58.309m

5 0
3 years ago
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