Answer:
The time is 0.563 ns.
Explanation:
Given that,
Index of refraction of glass = 1.41
Distance = 12.0 cm
Angle = 33.0°
We need to calculate the refraction angle
Using Snell's law
![n_{1}\sin\theta=n_{r}\sin\theta](https://tex.z-dn.net/?f=n_%7B1%7D%5Csin%5Ctheta%3Dn_%7Br%7D%5Csin%5Ctheta)
put the value into the formula
![1\times\sin33=1.41\sin\theta](https://tex.z-dn.net/?f=1%5Ctimes%5Csin33%3D1.41%5Csin%5Ctheta)
![\sin\theta=\dfrac{1\times\sin33}{1.41}](https://tex.z-dn.net/?f=%5Csin%5Ctheta%3D%5Cdfrac%7B1%5Ctimes%5Csin33%7D%7B1.41%7D)
![\theta=22.71^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D22.71%5E%7B%5Ccirc%7D)
We need to calculate the velocity of beam in glass
Using formula of velocity
![v=\dfrac{c}{n}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bc%7D%7Bn%7D)
Put the value into the formula
![v=\dfrac{3\times10^{8}}{1.41}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B3%5Ctimes10%5E%7B8%7D%7D%7B1.41%7D)
![v=2.13\times10^{8}\ m/s](https://tex.z-dn.net/?f=v%3D2.13%5Ctimes10%5E%7B8%7D%5C%20m%2Fs)
We need to calculate the time
Using formula of distance
![v=\dfrac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bd%7D%7Bt%7D)
![t=\dfrac{12.0\times10^{-2}}{2.13\times10^{8}}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B12.0%5Ctimes10%5E%7B-2%7D%7D%7B2.13%5Ctimes10%5E%7B8%7D%7D)
![t=5.63\times10^{-10}\ sec](https://tex.z-dn.net/?f=t%3D5.63%5Ctimes10%5E%7B-10%7D%5C%20sec)
![t=0.563\times10^{-9}\ sec](https://tex.z-dn.net/?f=t%3D0.563%5Ctimes10%5E%7B-9%7D%5C%20sec)
![t=0.563\ ns](https://tex.z-dn.net/?f=t%3D0.563%5C%20ns)
Hence, The time is 0.563 ns.
Answer:
5Hz
Explanation:
Frequency = No. of waves per second
10 waves are produced in 2 seconds
in one second 10/2 waves are produced
(ie) 5 waves are produced in 1 second
Therefore the frequency of wave is 5 Hz
<span>Plate tectonics suggest that the lithosphere floats and moves on the asthenosphere.</span>