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2 years ago

Why are the coral reefs suffering? (site 2) explain

Physics

2 answers:

MissTica2 years ago

6 0

Answer:

bcuz ov yo fat mamma

Explanation:

Naily [24]2 years ago

6 0

Answer:

Water pollution

Explanation:

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You move a 25 N object 5 meters. How much work did you do ?

olga55 [171]

The answer is 125 Joules

The first thing to take note of is the work equation: W=F×D

Since we already have our force and our distance that will help make this problem easier.

So, W=25*5

W=125

Therefore, our answer is 125 Joules since work is measured in joules

Hope this helped!! :)

3 0

3 years ago

a hot iron bar is placed 100ml 22C water. the water temperature rises to 32C. how much heat did the water gain and how much heat

Sergeu [11.5K]

Answer:

Water gained: 10
Iron lost: -10

Explanation:

Given: Hot iron bar is placed 100ml 22C water, the water temperature rises to 32C

To find: How much heat the water gain, how much heat did the iron bar lost

Formula:Q = change T x C x M

Solve:

How much heat water gained

Initial heat = 22, then rose to 32. To find how much heat the water gained, simply subtract the current heat by the initial heat.

32 - 22 = 10

The water gained 10 amounts of heat.

How much heat Iron lost

Current heat = 32, then dropped to 22. To find how much heat the Iron lost, simply subtract the initial heat by the current heat.

22 - 32 = -10

The Iron lost -10 amounts of water.

4 0

3 years ago

Two planets A and B, where B has twice the mass of A, orbit the Sun in elliptical orbits. The semi-major axis of the elliptical

lozanna [386]

Answer:

2.83

Explanation:

Kepler's discovered that the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit, that is called Kepler's third law of planet motion and can be expressed as:

$T=\frac{2\pi a^{\frac{3}{2}}}{\sqrt{GM}}$ (1)

with T the orbital period, M the mass of the sun, G the Cavendish constant and a the semi major axis of the elliptical orbit of the planet. By (1) we can see that orbital period is independent of the mass of the planet and depends of the semi major axis, rearranging (1):

$\frac{T}{a^{\frac{3}{2}}}=\frac{2\pi}{\sqrt{GM}}$

$\frac{T^{2}}{a^{3}}=(\frac{2\pi }{\sqrt{GM}})^2$ (2)

Because in the right side of the equation (2) we have only constant quantities, that implies the ratio $\frac{T^{2}}{a^{3}}$ is constant for all the planets orbiting the same sun, so we can said that:

$\frac{T_{A}^{2}}{a_{A}^{3}}=\frac{T_{B}^{2}}{a_{B}^{3}}$

$\frac{T_{B}^{2}}{T_{A}^{2}}=\frac{a_{B}^{3}}{a_{A}^{3}}$

$\frac{T_{B}}{T_{A}}=\sqrt{\frac{a_{B}^{3}}{a_{A}^{3}}}=\sqrt{\frac{(2a_{A})^{3}}{a_{A}^{3}}}$

$\frac{T_{B}}{T_{A}}=\sqrt{\frac{2^3}{1}}=2.83$

6 0

3 years ago

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WILL NAME BEST ANSWER THE BRAINLIEST (if you answer well)

mylen [45]

The best and most correct answer among the choices provided by the question is third choice. What happened during the set-up was the excess protons move from the positive rod to the negative rod. I hope my answer has come to your help. God bless and have a nice day ahead!

7 0

3 years ago

A lamp that uses 100.0 watts of power requires a voltage of 210.0 volts. What is the resistance of the lamp?

alexandr402 [8]

Resistance = Voltage/Current
Wattage = Voltage * Current

 That means the current drawn by the lamp is equal to 100 watts divided by 210 volts.

Resistance = $\frac{210}{ \frac{100}{210} }$

6 0

2 years ago

Read 2 more answers