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lora16 [44]
3 years ago
15

18

Engineering
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

englishhhhhhhhh

Explanation:

we dont understand

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Air enters a compressor operating at steady state at 1.05 bar, 300 K, with a volumetric flow rate of 21 m3/min and exits at 12 b
omeli [17]

Answer:

- 46.5171kW

Explanation:

FIrst, the value given:

P1 = 1.05 bar (Initial pressure)

P2 = 12 bar (final pressure)

Heat transfer, Q = - 3.5 kW (It is negative because the compressor losses heat to the surroundings)

Mgaseous nitrogen = Mair = 28.0134 Kg/mol (constant)

Universal gas constant, Ru = 8.3143 Kj/Kgmolk

Specific gas constant, R = 0.28699 Kj/KgK

Initial temperature, T1 = 300 K

Final temperature, T2 = 400 K

Finding the volume:

P1V1 = RT1

V1 = RT1 ÷ P1

= (0.28699 Kj/KgK X 300k) ÷ 105

Note convert bar to Kj/Nm by multiply it by 100

V1 =  0.81997 m3/Kg

To get the mass flow rate:

m = volumetric flow rate / V1

= (21 m3/min x 1/60seconds) ÷ 0.81997 m3/Kg

= 0.4268Kg/s

Using tables for the enthalpy,

hT1 = 300.19 KJ/Kg

hT2 = 400.98 KJ/Kg

The enthalpy change = hT2 - hT1

= 100.79 KJ/Kg

Power, P = Q - (m X enthalpy change)

= - 3.5 - (0.4268 X 100.79)

= - 46.5171kW

3 0
3 years ago
Explain the function and role of Product Teardown Charts, and describe how engineers utilize them in the reverse engineering pro
inn [45]

Answer:

Product deformulation analysis, also known as “chemical reverse engineering” is the process of analytically breaking down a drug, material, or product’s formulation to separate and determine the specific identity and exact quantity of both its major and minor constituent components. This process can be vital to a wide range of scenarios such as identifying hazardous components in consumer products, determining potential patent infringement, or improving competitive positioning of existing or new product(s).

Explanation:

8 0
3 years ago
Read 2 more answers
Identify three questions a patient might ask of the nuclear medicine technologist performing a nuclear medicine exam.
bogdanovich [222]

Answer:

How long is my nuclear medicine exam?

How long will the radioactivity stay in my system?

What are the risks?

Explanation:

3 0
2 years ago
Drag each item to the container that best describes it.
LenKa [72]

Answer:

If this is what I think it is...

Explanation:

Rate: 1 sheet per 4 paragraphs, 1 page for every four students

Unit Rate: 500 sheets per ream, 40 pages for each booklet, 15 pages for each booklet

Neither: 25 pages

Step-by-step explanation:

To do this you just need to remember the difference between Unit Rate and Rate, the Unit rate make reference to those rates in which the numerator is one, so you saying there are 3 candies for each kid, that is a unit rate, saying there is one kid for every three candies that is a rate, so that´s how you divide them, that´s why even though 1 sheet per 4 paragraphs, 1 page for every four students have one in their fractions, they are rates and not unit rates because the one is not in the numerator.

7 0
3 years ago
Read 2 more answers
Assume that each atom is a hard sphere with the surface of each atom in contact with the surface of its nearest neighbor. Determ
deff fn [24]

Answer:

The classification of the concern is listed in the interpretation segment below.

Explanation:

(a)...

<u>Simple cubic lattice</u>

<u />a=2r

Now,

The unit cell volume will be:

=a^3

=(2r)^3

=8r^3

At one atom per cell, atom volume will be:

=(1)\times (\frac{4 \pi r^3}{3})

Then the ratio will be:

Ratio=\frac{\frac{4 \pi r^3}{3}}{8r^3}\times 100 \ percent

        =52.4 \ percent

(b)...

<u>Diamond lattice</u>

The body diagonal will be:

d=8r=a\sqrt{3}

       a=\frac{8}{\sqrt{3}}r

The unit cell volume will be:

=a^1

=(\frac{8r}{\sqrt{3}})^1

At eight atom per cell, the atom volume will be:

=8(\frac{4 \pi r^1}{3})

Then the Ratio will be:

Ratio=\frac{8(\frac{4 \pi r^1}{3})}{(\frac{8r}{\sqrt{3}})^1}\times 100 \ percent

        =34 \ percent

Note: percent = %

5 0
3 years ago
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