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Minchanka [31]
3 years ago
8

James Stewart, 2002 Motorcross/Supercross Rookie of the Year, is leading a race when he runs out of gas near the finish line. He

is moving at 16 m/s when he enters a section of the course covered with sand where the effective coefficient of friction is 0.90. Will he be able to coast through this 15-m-long section to the finish line at the end? If yes, What is his speed at the finish line?
Physics
1 answer:
Flura [38]3 years ago
6 0
We are given the coefficient of friction which is:
Cf = 0.90
The acceleration based on this would be:
a = -Cf * g 
a = -0.90 * (9.81 m/s^2)
a = -8.83 m/s^2
Calculate the distance at his total stop v = 0 using the formula:
v^2 = vo^2 + 2ad
where v is final velocity = 0, vo is initial velocity = 16, d is distance
0 = 16^2 + 2 (-8.83) d
d = 14.5 m
So he is short by 0.5 m, he does not reach the finish line
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A battery with an internal resistance ofrand an emf of 10.00 V is connected to a loadresistorR=r. As the battery ages, the inter
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Answer:

The current is reduced to half of its original value.

Explanation:

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  • where Rint = r and RL = r
  • Replacing these values in I₁, we have:

       I_{1} = \frac{V}{R_{int} +r_{L} } = \frac{V}{2*r} (1)

  • When the battery ages, if the internal resistance triples, the new current can be found using Ohm's Law again:

       I_{2} = \frac{V}{R_{int} +r_{L} } = \frac{V}{(3*r) +r} = \frac{V}{4*r}  (2)

  • We can find the relationship between I₂, and I₁, dividing both sides, as follows:

        \frac{I_{2} }{I_{1} } = \frac{V}{4*r} *\frac{2*r}{V} = \frac{1}{2}

  • The current when the internal resistance triples, is half of the original value, when the internal resistance was r, equal to the resistance of the load.  
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3 years ago
what occurs when a swimmer pushes through the water to swim answers are (A) the water exerts a reaction force on the swimmer (B)
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When a swimmer pushes through water to swim they are propelled forward because of the water resistance against the hand and feet. It's A. The water doesn't automatically push the swimmer forward. It releases a reaction after the swimmer pushes through the water.
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Answer and Explanation:

Comparison between the Titan's atmosphere and earth atmosphere

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Wilma can mow a lawn in 80 minutes. Rocky can mow the same lawn in 120 minutes. Construct an equation that would allow you to de
xeze [42]

Answer:

t = 96 minutes

Explanation:

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so work done in 1 minute by Wilma is given as

W_1 = \frac{1}{80}

Similarly Rocky mow same lawn in 120 minute

so work done in 1 minute by Rocky is given as

W_2 = \frac{1}{120}

now we know that they both worked by "t" time

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Answer:

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Explanation:

We can solve the problem by applying Newton's second law of motion, which  states that:

\sum F=ma

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\sum F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, we have:

\sum F=30 N - 20 N = 10 N (to the left) is the net force on the object

m = 2.0 kg is the mass

So, the acceleration is:

a=\frac{\sum F}{m}=\frac{10}{2.0}=5.0 m/s^2

in the same direction as the force (left).

5 0
3 years ago
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