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eduard
3 years ago
13

What variable is the dependent variable? A. Time B. Temperature

Physics
2 answers:
ELEN [110]3 years ago
7 0
The Dependent variable is B or know as Temperature
melomori [17]3 years ago
6 0

Answer:

the answer is b temperature

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Why does magma rise from depth to the surface of the earth?
Viefleur [7K]

Answer

Magma is less dense compared to the surrounding rock.

the overlying rock creates pressure which forces the magma to be directed upward.

Explanation:

at high temperatures the magma is liquid form with the high energy which causes the formation of bonds and the pressure build up creates the increase  channeling of the liquid.as the temperature decreases the magma moves into the surface

6 0
3 years ago
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According to the graph above, how large of a force is needed in order to stretch the string 1.00 meters?
gulaghasi [49]

My guess for this one would be; 400 N

My reasoning would be; it starts at 0 on both X and Y, if you need to get to 1.00 meters thats 4/4. 1/4 of 1.00 is .25, and on .25 its on 100 so multiply it by 4 to make 1.00 and you get 400 N

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3 years ago
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Which has a greater velocity?
klio [65]
Your answer is the ball it's very simple a ball rolling down hill will be the one that makes the most sense.
8 0
3 years ago
A scientist tested Charles’s law, which states that volume is directly related to temperature. Assume constant pressure. What wi
sergeinik [125]

Based on the options given, the most likely answer to this query is 

B) as volume decreases, temperature decreases.
Charles' law states that when volume increase or decrease, accordingly, temperature becomes similar.

Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
5 0
3 years ago
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Two 2.0cm×2.0cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 v battery. What is the
Fantom [35]

Answer:

The charge on each electrode is

q=0.354 x10^{-12}

Explanation:

The charge to find the equation is development

V=9v

d=1.0 mm\\A=2cm*2cm=0.02m*0.02m\\A=4x10^{-4} \\E_{o} =8.85x10^{-12} (\frac{C^{2} }{N*m^{2} } )

q=C*V

C=\frac{E_{o}*A }{d} \\C=\frac{8.85x10^{-12} *4x10^{-4}  }{0.01}=0.354  \\

q=0.354*9v\\q=3.186x10^{-12} C

3 0
3 years ago
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