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sukhopar [10]
2 years ago
14

The mass of an electron is A) equal to the mass of a proton B) less than the mass of a neutron C) greater than the mass of a pro

ton D) equal to the mass of a neutron
Physics
1 answer:
julsineya [31]2 years ago
4 0

Answer:

B

Explanation:

Atomic structure contains electrons, protons and neutrons.

Electron is very light compared to proton and neutrons.

Given that the mass of an electron is

A) equal to the mass of a proton

B) less than the mass of a neutron

C) greater than the mass of a proton

D) equal to the mass of a neutron

The correct answer is B which is less than the mass of the neurons.

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A ball is dropped from the top of a building. it initially moves at 4.0 m/s. after 0.5 seconds, it moves at 3.8 m/s. what force
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Air resistance (meeting space requirements)

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A 1.2 kg hammer slams down on a nail at 5.0 m/s and bounces off at 1.0 m/s. If the impact lasts 1.0 ms, what average force is ex
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Answer:

Explanation:

Impulse results in a change of momentum

FΔt = mΔV

F = mΔV/Δt

The impulse acting on the hammer will equal the impulse acting on the nail

If we assume upward is the positive direction

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A copper telephone wire has essentially
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Answer:

128.21 m

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The following data were obtained from the question:

Initial temperature (θ₁) = 4 °C

Final temperature (θ₂) = 43 °C

Change in length (ΔL) = 8.5 cm

Coefficient of linear expansion (α) = 17×10¯⁶ K¯¹)

Original length (L₁) =.?

The original length can be obtained as follow:

α = ΔL / L₁(θ₂ – θ₁)

17×10¯⁶ = 8.5 / L₁(43 – 4)

17×10¯⁶ = 8.5 / L₁(39)

17×10¯⁶ = 8.5 / 39L₁

Cross multiply

17×10¯⁶ × 39L₁ = 8.5

6.63×10¯⁴ L₁ = 8.5

Divide both side by 6.63×10¯⁴

L₁ = 8.5 / 6.63×10¯⁴

L₁ = 12820.51 cm

Finally, we shall convert 12820.51 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

12820.51 cm = 12820.51 cm × 1 m / 100 cm

12820.51 cm = 128.21 m

Thus, the original length of the wire is 128.21 m

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Answer:

space , small amount of gravity is found in the space ,infact we can say that there is no gravity in the space

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