Answer: 2.17 g of bromide product would be formed
Explanation:
The reaction of calcium bromide with lithium oxide will be:

To calculate the moles :

As lithium oxide is in excess, calcium bromide is the limiting reagent.
According to stoichiometry :
1 mole of
produce = 2 moles of 
Thus 0.0125 moles of
will require=
of 
Mass of 
Thus 2.17 g of bromide product would be formed
The given statement is true.
A classic, predominantly silt-sized sediment, which is produced due to the gathering of wind-blown dust is known as loess. About 10 percent of the land region of the Earth is covered by loess or identical sediments. The loess seems to form into very rich soils. Under suitable climatic circumstances, it is one of the most agricultural productive terrains around the globe.
The soils formed by loess seems to be extremely drained. It is considered that the fertility of the loess soils is mainly because of porosity and cation exchange capacity.
The answer is B
To write the equilibrium constant for an equation, all you have to do is divide the products by the reactants. The reactants are always on the left side, and the products are always on the right side. The coefficients of the elements will be written as the exponent of that same element. However, in this equation, we do not have to write any exponents, as there are no coefficient but 1.
The radiation emitted is a beta particle with a -1 charge. Beta particles have a <span>medium penetrating power. An emission of beta particles requires shielding because of the hazards it pose to humans. Thus, one characteristic of this radiation is that <span>some shielding is required.</span></span>
Answer: Option (A) is the correct answer.
Explanation:
Atomic number of sodium is 11 and its electronic configuration is
.
In order to gain stability, sodium loses one electron and hence it forms a positive ion
.
Thus, we can conclude that when sodium combines with chlorine, it has a net charge of +1 because sodium loses a negative electron when forming chemical bonds.