The first thing you should do in this case is to realize that you have two different materials.
First we make a free body diagram.
Then, we use the definitions of mechanics to find the forces.
Finally we substitute the values to find the normal stress due to the load.
Solution attached.
Answer:
Explanation:
We use the harmonic motion position equation:
where A = 0.350 and for t = 0
so:
and also:
so we have:
x(t)=0.350cos(1.532 t)
For t = 3.403 s
x(3.403)=0.350cos(1.532 (3.403)) = 0.348 m
Answer:
Explanation:
the resistance of a electrical device
R = V² / P where V is volt and P is power .
The devices are in parallel so same volt will apply on them
So R₁ = 12² / 32.5 = 4.431 ohm
R₂ = 12² / 2 x 10³ = .072 ohm
when they are in series
Common Current in them = 12 / 4.431 + .072
= 2.6649 A
power consumed by first device when they are in series
= current² x resistance
= 2.6649² x 4.431 = 31.46 W
power consumed by other
= 2.6649² x .072 = .511 W
Answer:
a = 5.65 m/s² (↑)
Explanation:
T = 34.012 N (↑)
m = 2.2 Kg
g = 9.81 m/s²
We apply Newton's 2nd Law as follows:
∑ Fy = m*a
⇒ T - W = m*a
⇒ T - m*g = m*a
⇒ a = (T - m*g) / m
Finally
⇒ a = (34.012 N - 2.2 Kg*9.81 m/s²) / 2.2 Kg
⇒ a = 5.65 m/s² (↑)
For this problem, we use our knowledge on trigonometric functions on a right triangle to be able to calculate for the x and y components of the walk. We do as follows:
sin 60 = ax / 9.4
ax = 8.14
cos 60 = ay / 9.4
ay = 4.7