Question

A sample of Ne gas has a pressure of 654 mmHg with an unknown volume. The gas has a pressure of 345 mmHg when the volume is 495mL with no change in temperature or amount of gas. What is the initial volume in milliliters of the gas?

Answer 1

Answer:

The initial volume of Ne gas is 261mL

Explanation:

This question can be answered using Ideal Gas Equation;

However, the following are the given parameters

Initial Pressure = 654mmHg

Finial Pressure = 345mmHg

Final Volume = 495mL

Required

Initial Volume?

The question says that Temperature is constant;

This implies that, we'll make use of Boyle's law ideal gas equation which states;

$P_1V_1 = P_2V_2$

Where $P_1$ represent the initial pressure

$P_2$ represent the final pressure

$T_1$ represent the initial temperature

$T_2$ represent the final temperature

$P_1 = 654mmHg\\P_2 = 345mmHg\\V_2 = 495mL$

Substitute these values in the formula above;

$654 * V_1 = 345 * 495$

$654V_1 = 170775$

Divide both sides by 654

$\frac{654V_1}{654} = \frac{170775}{654}$

$V_1 = \frac{170775}{654}$

$V_1 = 261.123853211$

$V_1 = 261mL$ (Approximated)

The initial volume of Ne gas is 261mL