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Pani-rosa [81]
3 years ago
9

What is the acceleration of an object that has a velocity of 18 m/s and is moving in a circle of radius 30m?

Physics
2 answers:
blsea [12.9K]3 years ago
5 0
Acceleration = V^2/r = 18^2/ 30 = 10.8 m/s^2
insens350 [35]3 years ago
4 0

Well, first of all, 18 m/s is the object's speed, but not its velocity.
Velocity consists of the object's speed AND direction, and this
particular object's direction is constantly changing, since it's
moving around a circle.  So its velocity is constantly changing too.

Centripetal acceleration  =  (speed)² / (radius)

                                           =  (18 m/s)² / (30 m)

                                           = (324 m²/s²) / (30 m)

                                           =       10.8 m/s²

                                       (about  1.1 G)   
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We wrap a light, nonstretching cable around a 10.0 kg kg solid cylinder with diameter of 38.0 cm cm . The cylinder rotates with
amm1812

Answer: 14.16

Explanation:

Given

d = 38cm

r = d/2 = 38/2 = 19cm = 0.19m

K.E = 510J

m = 10kg

I = 1/2mr²

I = 1/2*10*0.19²

I = 0.18kgm²

When it has 510J of Kinetic Energy then,

510J = 1/2Iω²

ω² = 1020/I

ω² = 1020/0.18

ω² = 5666.67

ω = √5666.67 = 75.28 rad/s

Velocity is the block, v = ωr

V = 75.28 * 0.19

V = 14.30m/s

The "effective mass" M of the system is

M = (14.0 + ½*10.0) kg = 19.0 kg

The motive force would be

F = ma

F = 14 * 9.8

F = 137.2N

so that the acceleration would be

a = F/m

a = 137.2/19

a = 7.22m/s²

Finally, using equation of motion.

V² = u² + 2as

14.3² = 0 + 2*7.22*s

204.49 = 14.44s

s = 204.49/14.44

s = 14.16m

6 0
3 years ago
Argon makes up 0.93% by volume of air. Calculate its solubility (in mol/L) in water at 20°C and 1.0 atm. The Henry's law constan
vladimir2022 [97]

Answer:

S= 1.40x10⁻⁵mol/L

Explanation:

The Henry's Law is given by the next expression:

S = k_{H} \cdot p (1)

<em>where S: is the solubility or concentration of Ar in water, k_{H}: is Henry's law constant and p: is the pressure of the Ar </em>

<u>Since the argon is 0.93%, we need to multiply the equation (1) by this percent:</u>

S = 1.5 \cdot 10^{-3} \frac{mol}{L\cdot atm} \cdot 1.0atm \cdot \frac{0.93}{100} = 1.40 \cdot 10^{-5} \frac{mol}{L}

Therefore, the argon solubility in water is 1.40x10⁻⁵mol/L.

Have a nice day!          

8 0
3 years ago
What is the resulting direction of a surface wave?​
german

surface wave is a wave that travels along the surface of a medium. The medium is the matter through which the wave travels. Ocean waves are the best-known examples of surface waves. They travel on the surface of the water between the ocean and the air.

HOPE IT HELPS

7 0
3 years ago
Read 2 more answers
A car radio draws 0.27 A of current in the autos 12-V electrical system. (a) How much electric power does the radio use?
Lostsunrise [7]

Answer:

(a) 3.24 w (b) 44.44 ohm

Explanation:

It is given that car draws 0.27 A current so current I = 0.27 A

The system has a voltage of 12 V

(a) Electrical power = voltage ×current =12\times 0.27=3.24W

(b) The resistance is defined as the ratio of voltage and current

So resistance R=\frac{V}{I}=\frac{12}{0.27}=44.44 ohm

8 0
3 years ago
g typical coffee mug holds up to 12 oz (340 grams) of water. How much heat energy is required to warm enough water from 23⁰C to
Kryger [21]

Answer:

Explanation:

Heat required to raise the temperature

= mass x specific heat x rise in temperature

= .34 x 4200 x ( 95 - 23 )

= 102816 J .

1 kWh = 1000 x 60 x 60 J

= 3600000 J

102816 J  = 102816 / 3600000

= .02856 kWh .

8 0
3 years ago
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