Question

A truck is speeding up as it travels on an interstate. The truck's momentum (in kg · m/s) is proportional to the truck's speed (in m/s). a) At some moment the truck's momentum is 48300 kg · m/s and the truck's speed is 23 m/s. At this moment, the truck's momentum (in kg · m/s) is how many times as large as the truck's speed (in m/s) ______________. b) This means that as the truck travels, the truck's momentum (in kg · m/s) is always ______________ times as large as the truck's speed (in m/s). c) If the truck is traveling at 17 m/s, what is the momentum (in kg m/s) ______________.

Answer 1

Answer:

a)48300 times

b)P = 821100  kg · m/s

Explanation:

Given that

m = 48300 kg

v= 23 m/s

We know that linear momentum (P) given as

P = m v

P = 48300 x 23  kg · m/s

So we can say that truck momentum is 48300 times its velocity.

Now given that

v= 17 m/s

P = m v

P = 48300 x 17  kg · m/s

P = 821100  kg · m/s

Answer 2

Answer:

a) 2100, b) 2100, c) $p = 35700\,\frac{kg\cdot m}{s}$

Explanation:

a) At some moment the truck's momentum is 48300 kg · m/s and the truck's speed is 23 m/s. At this moment, truck's momentum (in kg · m/s) is how many times as large as the truck's speed (in m/s):

$i = \frac{48300\,\frac{kg\cdot m}{s} }{23\,\frac{m}{s} }$

$i = 2100$

b) This means that as the truck travels, the truck's momentum (in kg · m/s) is always 2100 times as large as the truck's speed (in m/s).

c) If the truck is traveling at 17 m/s, what is the momentum (in kg m/s):

$p = \frac{17\,\frac{m}{s} }{23\,\frac{m}{s} } \cdot \left(48300\,\frac{kg\cdot m}{s} \right)$

$p = 35700\,\frac{kg\cdot m}{s}$