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igor_vitrenko [27]
3 years ago
10

A vacuum cleaner has a rating of 460 W on 230 V mains. The value of the fuse connected in the plug will be

Physics
1 answer:
amid [387]3 years ago
7 0

Answer:

2 amps

Explanation:

Given data

Power = 460W

voltage= 230V

Required

The amperage/ current of the fuse

Recall  P= IV

I= P/V

I= 460/230

I=2 amps

Hence the current of the fuse is 2 amps

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A well lagged copper calorimeter of mas 120g contains 70g of water and 10g ice both at 0°C . Dry steam at 100°C is passed in unt
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Answer:

7.6 g

Explanation:

"Well lagged" means insulated, so there's no heat transfer between the calorimeter and the surroundings.

The heat gained by the copper, water, and ice = the heat lost by the steam

Heat gained by the copper:

q = mCΔT

q = (120 g) (0.40 J/g/K) (40°C − 0°C)

q = 1920 J

Heat gained by the water:

q = mCΔT

q = (70 g) (4.2 J/g/K) (40°C − 0°C)

q = 11760 J

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q = mL + mCΔT

q = (10 g) (320 J/g) + (10 g) (4.2 J/g/K) (40°C − 0°C)

q = 4880 J

Heat lost by the steam:

q = mL + mCΔT

q = m (2200 J/g) + m (4.2 J/g/K) (100°C − 40°C)

q = 2452 J/g m

Plugging the values into the equation:

1920 J + 11760 J + 4880 J = 2452 J/g m

18560 J = 2452 J/g m

m = 7.6 g

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