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Juliette [100K]
3 years ago
15

Most stars are a.brown fs b.main sequence c.white dwarfs d.pulsars

Physics
1 answer:
trapecia [35]3 years ago
3 0
I believe the answer is B. Main sequence 
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What is the full moon that occurs during the autumn equinox called?
zhannawk [14.2K]

Answer: Harvest Moon

Explanation:

But to most casual observers, the moon will appear fully illuminated in the night sky from Sunday through Tuesday. In the Northern Hemisphere, the full moon that appears closest to the fall equinox is traditionally referred to as the "Harvest Moon."

3 0
2 years ago
The blackbody emission spectrum of object A peaks in the ultraviolet region of the electromagnetic spectrum at a wavelength of 2
seraphim [82]

Answer:

A) Object A is 3.25 times hotter.

B) Object A radiates 111.6 times more energy per unit of area.

Explanation:

Wiens's law states that there is an inverse relationship between the wavelength in which there is a peak in the emission of a black body and its temperature, mathematically,

\lambda_{peak}= \dfrac{0.0028976}{T},

where T is the temperature in kelvins and, \lambda_{peak} is the wavelenght (in meters) where the emission is in its peak.

From here, if we solve Wien's law for the temperature we get

T=\dfrac{0.0028976}{\lambda_{peak}}.

Now, we can easily compute the temperatures.

For object A:

T_{A}=\dfrac{0.0028976}{200*10^{-9}}

T_{A}=14488K.

For object B:

T_{B}=\dfrac{0.0028976}{650*10^{-9}}

T_{B}=4458K

From this, we get that

T_{A}/T_{B}=3.25,

which means that object A is 3.25 times hotter.

Stefan's Law states that a black body emits thermal radiation with power proportional to the fourth power of its temperature.

This is

E=\sigma T^{4},

where  \sigma=5.67*10^{-8}\ Wm^{-2}K^{-4} is call the Stefan-Boltzmann constant.

From this, power can be easily compute:

E_{A}=(5.67*10^{-8}*(14488)^{4})=2.5*10^{9}W\\E_{B}=(5.67*10^{-8}*(4458)^{4})=22.4*10^{6}}W,

and we can notice that

E_{A}/E_{B}=111.6,

which means that object A radiates 111.6 time more energy per unit of area.

8 0
3 years ago
A crane lifts a 425 kg steel beam vertically a distance of 64 m. How much work does the crane do on the beam if the beam acceler
Arisa [49]

Answer:

<h2>work done= 48.96 kJ</h2>

Explanation:

Given data

mass of  load m= 425 kg

height/distance h=64 m

acceleration a= 1.8 m/s^2

The work done can be calculated using the expression

work done= force* distance

but force= mass *acceleration

hence work done= 425*1.8*64= 48,960 J

work done= 48.96 kJ

3 0
3 years ago
A solid, uniform sphere of mass 2.0 kg and radius 1.7 m rolls without slipping down an inclined plane of height 5.3 m. what is t
inn [45]
<span>Answer: Total kinetic energy at the bottom = 0.5(1+0.4) mv^2 = mgh V^2 = 7*9.8/0.7 V = 9.9m/s ω = V/r = 9.9/1.7 = 5.8rad/s Answer c. 5.8 rad/s</span>
7 0
3 years ago
What is the mass of an object if it took 270 J of work to move it 15 meters? Please help!
maxonik [38]
That depends upon the direction the object moves
5 0
3 years ago
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