Moment of inertia for one rod is expressed as:
<span>
I(1)= I(end) + md^2 = (1\12)mL^2+m(L/2√2)^2=(5/24)mL^2
</span><span>
Therefore, for two rods:
</span><span>
I2 = 2I1 = (5/12)mL^2
</span><span>
For the moment of inertia at the pivot point,
</span><span>
I=I2+2md^2=(5/12)mL^2+2(m(L/2√2)^2)=(2/3)mL^2
</span><span>
Substituting the equations above to the equation for frequency:
</span><span>
f=(1/2π)√(2mgd/I)=(1/4π)√(6g/√2L)</span>
Answer:
from the position of the center of the Sun
Explanation:
As we know that mass of Sun and Jupiter is given as


distance between Sun and Jupiter is given as

now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them
so we will have


from the position of the center of the Sun