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vichka [17]
4 years ago
6

-

Chemistry
1 answer:
ioda4 years ago
5 0

Answer:

02

Explanation:

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What is the chemical formula for one base that does not contain OH-
andre [41]
NH3

(ammonia is a weak base)

Hope that helps
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3 years ago
Polly did on experiment with marbles in a glass
Setler79 [48]

Answer:

Polly did an experiment with marbles in a glass bowl to show the movement of particles in solids, liquids, and gases. The experimental set-up is shown below: A glass bowl is shown with four marbles inside it. ... Add water to the bowl so that the marbles start sliding past one another

Explanation:

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3 years ago
Read 2 more answers
How many grams are in 1.76 x 10^23 atoms of iodine
Mariana [72]

Answer:

\boxed {\boxed {\sf About \ 37.1 \ grams \ of \ iodine }}

Explanation:

To convert from atoms to grams, you must first convert atoms to moles, then moles to grams.

1. Convert Atoms to Moles

To convert atoms to grams, Avogadro's number must be used.

6.022*10^{23}

This number tells us the number of particles (atoms, molecules, ions, etc.) in 1 mole. In this case, the particles are atoms of iodine.

\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Multiply the given number of atoms by Avogadro's number.

1.76*10^{23} \ atoms \ I*\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Flip the fraction so the atoms of iodine will cancel out.

1.76*10^{23} \ atoms \ I*\frac{  1 \ mol \ I}{6.022*10^{23} \ atoms \ I}

1.76*10^{23}* \frac{1 \ mol \ I}{6.022*10^{23} }

Multiply so the problem condenses into 1 fraction.

\frac{1.76*10^{23} \ mol \ I}{6.022*10^{23} }

0.2922617071 \ mol \ I

2. Convert Moles to Grams

Now we must use the molar mass of iodine, which is found on the Periodic Table.

  • Iodine Molar Mass: 126.9045 g/mol

Use this mass as a fraction.

\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply this fraction by the number of moles found above.

0.2922617071 \ mol \ I*\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply. The moles of iodine will cancel.

0.2922617071 *\frac{ 126.9045 \ g\ I }{ 1 }

The 1 as a denominator is insignificant.

0.2922617071 *{ 126.9045 \ g\ I }

37.08932581 \ g \ I

3. Round

The original measurement of 1.76*10^23 has 3 significant figures (1, 7, and 6). Therefore we must round our answer to 3 sig figs. For this answer, that is the tenths place.

37.08932581 \ g \ I

The 8 in the hundredth place tells us to round the 0 up to a 1.

\approx 37.1\ g \ I

There is about <u>37.1 grams of iodine </u>in 1.76*10^23 atoms.

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3 years ago
How many moles of KOH are in 130.0 mL of a 0.85 M solution of KOH?
iris [78.8K]
The answer is in the attached photo

3 0
3 years ago
2Al(s)+Fe2O3(s) → Al2O(s)+2Fe(s) with a delta H=-847 KJ.
Scrat [10]

∆H for given reaction -847kJ

  • As it's negative reaction is exothermic

So

2 mol of Al releases 847KJ heat

4 mol Al releases

  • 2(847)
  • 1694KJ

∆H=-1694KJ

5 0
2 years ago
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