Answer: The given substances are placed in order from most soluble in water to least soluble in water as follows.
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Explanation:
It is known that like dissolves like which means a polar compound will be soluble in a polar solvent. And, a non-polar compound will be soluble in non-polar solvent.
Ionic compounds are soluble in polar solvent like water. For example,
is an ionic compound and it is readily soluble in water.
2-butanol (
) is also a polar compound and it will also dissolve in water but to a lesser extent as compared to magnesium chloride.
Whereas both methane and propane are non-polar in nature. But as propane is larger in size as compared to methane so, it will be slightly more soluble in water as compared to methane.
Thus, we can conclude that the given substances are placed in order from most soluble in water to least soluble in water as follows.
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It must be made of matter because anything and everything is made up of atoms. The other three options are made of atoms but they are also matter.
<h3><u>Answer;</u></h3>
Polar: IF, PCl3, IF5
Nonpolar: CS2, SO3, SF6
<h3><u>Explanation:</u></h3>
- Polar molecules form when two atoms do not share electrons equally in a covalent bond.
- A molecule is classified as a polar molecule when the arrangement of the atoms is such that one end of the molecule has a positive electrical charge and the other end has a negative charge.
- A non-polar molecule does not have electrical poles.The electrons are distributed more equally.
- Therefore, a non-polar molecule does not have a profusion of charges at the opposite ends. The majority of hydrocarbon liquids are non-polar molecules.
Answer:
[HI] = 0.7126 M
Explanation:
Step 1: Data given
Kc = 54.3
Temperature = 703 K
Initial concentration of H2 and I2 = 0.453 M
Step 2: the balanced equation
H2 + I2 ⇆ 2HI
Step 3: The initial concentration
[H2] = 0.453 M
[I2] = 0.453 M
[HI] = 0 M
Step 4: The concentration at equilibrium
[H2] = 0.453 - X
[I2] = 0.453 - X
[HI] = 2X
Step 5: Calculate Kc
Kc = [Hi]² / [H2][I2]
54.3 = 4x² / (0.453 - X(0.453-X)
X = 0.3563
[H2] = 0.453 - 0.3563 = 0.0967 M
[I2] = 0.453 - 0.3563 = 0.0967 M
[HI] = 2X = 2*0.3563 = 0.7126 M