All categories

4 years ago

According to Newton’s first law of motion, when will an object at rest begin to move?

2 answers:

8 0

Newton's first law of motion says something like "An object remains
in constant, uniform motion until acted on by an external force".

Constant uniform motion means no change in speed or direction.
If an object changes from rest to motion, that's definitely a change
of speed. So it doesn't remain in the state of constant uniform
motion (none) that it had when it was at rest, and that tells us
that an external force must have acted on it.

katen-ka-za [31]4 years ago

7 0

Answer:

Then the two forces acting on the body are equal.

Explanation:

You might be interested in

Explain why sugar was used in this experiment. How does the experiment relate to a baker adding yeast to bread to make it rise?

tia_tia [17]

Answer:

Yeast can use oxygen to release the energy from sugar (like you can) in the process called "respiration". ... So, the more sugar there is, the more active the yeast will be and the faster its growth (up to a certain point - even yeast cannot grow in very strong sugar - such as honey).

7 0

2 years ago

The force of gravity acting upon an object is the objects mass. True or false

rosijanka [135]

False , because mass is the amount of matter contains

4 0

3 years ago

Un cuerpo de 60 kg se encuentra a una distancia de 3.5 m del otro cuerpo, de manera que entre ellos se produce una fuerza de 6.5

aev [14]

Answer:

1989.6Kg

Explanation:

The computation of the mass of the other body is given below:

As we know that

F = G × m1 × m2 ÷ r²

Here the G would have the constant value i.e. 6.67 × 10^-11Nm² / kg².

Now

6.5 × 10^-7N = 6.67 × 10^-11Nm² / kg² × 60Kg × m2 / (3.5m) ²

m2 = (F × r²) / (G × m1)

m2 = (6.5 × 10^-7N × (3.5m) ²) ÷ (6.67 × 10^-11Nm² / kg² × 60Kg)

= 1989.6Kg

7 0

3 years ago

A student wanted to test how the mass of a paper airplane affect the distance it will fly paper clips were added before each tes

aksik [14]

IV - paper clip amount
DV - amount it flies
Control - I don't know this one
Constant - the airplane and force used to throw the airplane

6 0

3 years ago

Read 2 more answers

Help ppls thank u guys <3

Naddik [55]

Answer:

The magnitude of the sum of the two vectors is approximately 169.34 m

Explanation:

The given vectors are;

Vector B;

Magnitude = 101 m

Direction = 60.0° (30.0° west of north)

Resolving the vector into its x and y component vectors gives;

$\underset{B}{\rightarrow}$ = 101 × cos(60.0°)·i + 101 × sin(60.0°)·j = 55·i + 55·√3·j

∴ $\underset{B}{\rightarrow}$ = 55·i + 55·√3·j

Vector A;

Magnitude = 85.0 m

Direction = West

Resolving the vector into its x and y component vectors gives;

$\underset{A}{\rightarrow}$ = 85.0 × cos(0.0°)·i + 85.0 × sin(0.0°)·j = 85.0·i + 0·j

∴ $\underset{A}{\rightarrow}$ = 85.0·i

The sum of the two vectors is $\underset{B}{\rightarrow}$ + $\underset{A}{\rightarrow}$ = 55·i + 55·√3·j + 85.0·i = 140.0·i + 55·√3·j

The direction of the sum of the two vectors, θ = arctan(y-component of the vector)/(x-component of the vector))

Therefore, θ = arctan((55·√3)/140) ≈ 34.23° north of west or 55.77° west of north

The magnitude of the sum of the two vectors, R is R = √(140² + (55·√3)²) ≈ 169.34 m.

6 0

3 years ago