A gun is fired on a day when the speed of sound is 335 m/s and an echo is heard 0.75 seconds later. How far away is the object t
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Taking specific heat of lead as 0.128 J/gK = c
We have energy of ball at 7.00 meter height = mgh =
When leads gets heated by a temperature ΔT energy needed = mcΔT
= ΔT
Comparing both the equations
=
ΔT
ΔT = 0.536 K
Change in temperature same in degree and kelvin scale
So ΔT = 0.536