Answer:
Are barium and chlorine a metal and nonmetal?
Explanation:
I had the same question, and my class reviewed the test and this was the answer to this question.
Answer:
4000 L
Explanation:
Step 1:
Data obtained from the question. This include the following:
Initial volume (V1) = 2000 L.
Initial temperature (T1) = 100 K.
Initial pressure (P1) = 100 kPa.
Final temperature (T2) = 400 K.
Final pressure (P2) = 200 kPa.
Final volume (V2) =..?
Step 2:
Determination of the new volume of the gas.
The new volume of the gas can be obtained by using the general gas equation as follow:
P1V1/T1 = P2V2/T2
100 x 2000/100 = 200 x V2/400
Cross multiply to express in linear form.
100 x 200 x V2 = 100 x 2000 x 400
Divide both side by 100 x 200
V2 = (100 x 2000 x 400)/(100 x 200)
V2 = 4000 L
Therefore, the new volume of the gas is 4000 L
Moon reflects the light frim the sun, thats why we are able to see it and it shines in the night. But, we know that Earth revolves around Sun and Moon revolves around Earth. During this revolution, Earth and Moon comes in a position when Earth is in the middle of the Moon and Sun. So, it blocks the light of Sun frim reaching Moon. Hence, we see no reflection and it causes Lunar eclipse.
<h3>
Answer:</h3>
89.88° C
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of gold cylinder as 75 g
- specific heat of gold is 0.129 J/g°C
- Initial temperature of gold cylinder is 65°C
- Mass of water is 500 g
- Initial temperature of water is 90 °C
We are required to calculate the final temperature;
- We know that Quantity of heat is given by the product of mass, specific heat capacity and change in temperature.
<h3>Step 1: Calculate the quantity of heat absorbed by the Gold cylinder</h3>
Assuming the final temperature is X° C
Then; ΔT = (X-65)°C
Therefore;
Q = 75 g × 0.129 J/g°C × (X-65)°C
= 9.675X - 628.875 Joules
<h3>Step 2: Calculate the quantity of heat released by water</h3>
Taking the final temperature as X° C
Change in temperature, ΔT = (90 - X)° C
Specific heat capacity of water is 4.184 J/g°C
Therefore;
Q = 500 g × 4.184 J/g°C × (90 - X)° C
= 188,280 -2092X joules
<h3>Step 3: Calculate the final temperature, X°C</h3>
we know that the heat gained by gold cylinder is equal to the heat released by water.
9.675X - 628.875 Joules = 188,280 -2092X joules
2101.675 X = 188908.875
X = 89.88° C
Thus, the final temperature is 89.88° C
A...because both of them(carbon and oxygen)are nonmetal
