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STALIN [3.7K]
3 years ago
7

lenny accidentally drops his matchbox car into a graduated cylinder. if the car has a mass of 10 grams and the water level in th

e cylinder rises from 41 ml to 46 ml. determine the density of the matchbox car. the formula for density is d = m v
Physics
2 answers:
mezya [45]3 years ago
5 0

Answer: Denisty = 2.0 g/mL

Density =\frac{Mass}{volume}

The mass of the matchbox is, m = 10 g

The volume of the cylinder = volume of water displaced in the cylinder when matchbox is immersed = final volume - initial volume.

V=v_f-v_i=46 mL-41 mL=5.0 mL

Density =\frac{Mass}{volume}=\frac{10g}{5mL}=2.0g/mL

Hence, the density of matchbox is 2.0 g/mL

Rina8888 [55]3 years ago
4 0
Density formula is:
D = m / V
Volume of the matchbox car:
V = 46 ml - 41 ml = 5 ml = 0.005 l = 0.005 dm³
D = 10 g / 0.005 dm³
D = 2000 g / dm³ = 2 kg / dm³ = 2 × 10 ^(-3) kg/m³
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Mnenie [13.5K]
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6 0
3 years ago
While standing at the edge of the roof of a building, a man throws a stone upward with an initial speed of 6.95 6.95 m/s. The st
qwelly [4]

Answer:

18.1347 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² = a

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-6.95^2}{2\times -9.81}\\\Rightarrow s=2.4619\ m

Total height the ball falls is 2.4619+14.3 = 16.7619 m

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 16.7619+0^2}\\\Rightarrow v=18.1347\ m/s

The speed at which the stone reaches the ground is 18.1347 m/s

8 0
3 years ago
Concrete is pumped from a cement mixer to the place it is being laid, instead of being carried in wheelbarrows. The flow rate is
max2010maxim [7]

Answer:

a. 2.4 ×109  N ⋅ m2/s

b. 48.3 N⋅s /m2  

c. 8.00×104W

Explanation:

See Attached file for explanation

3 0
3 years ago
What is the density of a 150cm 3 block with a mass of 700 grams?
Vinvika [58]

Answer:

The Density of the block is 4.667g/mL

Explanation:

Given the following data;

Mass of block = 700g

Volume of block = 150cm³

Density = ?

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the equation;

Density = \frac{mass}{volume}

Substituting into the equation, we have;

Density = \frac{700}{150}

<em>Density = 4.667g/mL</em>

3 0
3 years ago
A girl drops a stone from the top a tower 45m tall. At the same time, a boy standing at the base of the tower, projects another
Advocard [28]

Answer:

(i) The stones meet at 1.8 second

(ii) The point at which the stones meet, is 28.8 m above the base of the building and 16.2 m below the top of the building.

Explanation:

(i)

First we consider the stone dropped by the girl. We have data:

Vi = Initial Velocity of Stone = 0 m/s   (Since the stone was initially at rest)

t = Time Period

g = 10 m/s²

s₁ = Distance Covered by Stone

Using 2nd equation of motion, we get:

s₁ = Vi t + (0.5)gt²

s₁ = (0)(t) + (0.5)(10)t²

s₁ = 5t²   ----- equation (1)

Now, we consider the stone throne vertically upward by the boy. We have data:

Vi = Initial Velocity of Stone = 25 m/s

t = Time Period

g = - 10 m/s²   (negative sign due to upward motion)

s₂ = Distance Covered by Stone

Using 2nd equation of motion, we get:

s₂ = Vi t + (0.5)gt²

s₂ = (25)(t) + (0.5)(-10)t²

s₂ = 25t - 5t²   ----- equation (2)

At, the point where both the stones meet, the sum of distances covered by both stones must be equal to the height of building (i.e 45 m).

s₁ + s₂ = 45

using values from equation (1) and equation (2)

5t² + 25t - 5t² = 45

25t = 45

t = 45/25

<u>t =  1.8 sec</u>

(ii)

using this value of of t in equation (2)

s₂ = (25)(1.8) - (5)(1.8)²

<u>s₂ = 28.8 m</u>

using this value of of t in equation (1)

s₁ = (5)(1.8)²

<u>s₁ = 16.2 m</u>

<u>Hence, the point at which the stones meet, is 28.8 m above the base of the building and 16.2 m below the top of the building.</u>

6 0
3 years ago
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